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Sauron [17]
2 years ago
12

If the specific heat of a material is 0.416 J/(g°C) and sample absorbs 50 J when it is heated from 30°C to 50°C what is the mass

of the sample?
Chemistry
1 answer:
ololo11 [35]2 years ago
5 0

The mass of the sample of the material is 0.1664 g.

<h3 /><h3>What is specific heat?</h3>

The amount of energy needed to raise the temperature of one gram of a substance by one degree Celsius.

By the formula of specific heat

Q = mc \Delta T

Given, that the specific heat (c) of material is 0.416 J/gC

The difference in temperatures is 30°C to 50°C

The mass=?

Q = heat, 50 J

Putting the values in the equation

\rm 50\;J = m \times 0.416 J/g^\circ C \times (50 - 30)\\\\m = \dfrac{0.416 J/g^\circ C \times 20}{50} = 0.1664 g

Thus, the mass of the samples is 0.166 g.

Learn more about specific heat

brainly.com/question/11297584

#SPJ1

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Answer:

You see the concentration decreased ten fold, from 1 M to 0.1 M.

You can simply increase the volume by ten times.

For example

If you have 250 mL of 1 molar HCl, you can add distilled water upto 2500 mL. Now the concentration is 0.1 molar.

If you want to use the serial dilution method, you can use the C1V1=C2V2 equation.

C1 = starting concentration.

C2 = final concentration.

V is for volume.

So let's say you have 500 mL of 1 M HCl and you only want 50 mL of 0.1 M HCl.

1 M x V1 = 0.1 M x 50 mL

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Explanation:

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3 years ago
The rate constant for the first-order decomposition of N2O5 (g) to NO2 (g) and O2 (g) is 7.48 * 10-3 s-1 at a given temperature.
alina1380 [7]

Answer:

Explanation:

In this problem, we have a first-order decomposition reaction with a given rate constant. The rate law for a first-order reaction like this is

r

a

t

e

=

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A

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rate = −d[A]dt = k[A]

[A]f =[A]i e−kt

We want the total pressure of the reaction chamber to be 0.145 atm, with a starting reactant pressure of 0.110 atm. To solve for the time this reaction takes, we need the reaction equation:

2N2O5(g) → 4NO2(g) + O2(g)

Using the stoichiometry of the reaction equation, we can determine the final pressure of the reactant. This requires us to rewrite the total pressure equation in terms of the change in pressure of the reactant.

Pf=0.145atm

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This comes from the stoichiometry.

pNO2 = 2(pN2O5i − pN2O5f )

This comes from the stoichiometry.

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0.145atm =(0.110atm + ΔpN2O5) − 2.5ΔpN2O5 = 0.110atm − 1.5ΔpN2O5

ΔpN2O5 = −0.0233atm

pN2O5f = 0.110atm − 0.0233atm =

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They contain the same number of molecules; however, the masses can differ depending on the molar masses of the substances.
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