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Sauron [17]
2 years ago
12

If the specific heat of a material is 0.416 J/(g°C) and sample absorbs 50 J when it is heated from 30°C to 50°C what is the mass

of the sample?
Chemistry
1 answer:
ololo11 [35]2 years ago
5 0

The mass of the sample of the material is 0.1664 g.

<h3 /><h3>What is specific heat?</h3>

The amount of energy needed to raise the temperature of one gram of a substance by one degree Celsius.

By the formula of specific heat

Q = mc \Delta T

Given, that the specific heat (c) of material is 0.416 J/gC

The difference in temperatures is 30°C to 50°C

The mass=?

Q = heat, 50 J

Putting the values in the equation

\rm 50\;J = m \times 0.416 J/g^\circ C \times (50 - 30)\\\\m = \dfrac{0.416 J/g^\circ C \times 20}{50} = 0.1664 g

Thus, the mass of the samples is 0.166 g.

Learn more about specific heat

brainly.com/question/11297584

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Complete Question

The complete question is shown on the first uploaded image  

Answer:

a

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      From the question we are told that

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                      NO_2_{(g)} + F_2 _{(g)} ----> NO_2 F_{(g)} + F_{(g)}

                      F_{(g)} +  NO_2 _{(g)} ---> NO_2 F_{(g)}

The overall balanced equation is

              2NO_2 _{(g)} +  F_2_{(g)} ---->  2NO_2 F_{(g)}

We combined the first reactant and the last product and the balanced the number of mole

     The observable rate law is

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Predict the splitting pattern for each of the labeled hydrogens in the following molecules. Assume that all coupling constants a
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Complete Question

The complete question is shown on the first uploaded image

Answer:

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Splitting pattern for Hb and Hc= 3+1 , Quartet

For Proton Hd, number of non equivalent protons n= 0

Splitting pattern for Hd= 0+1 , Singlet

b) Splitting pattern for Ha= 2+1 , Triplet

For Proton Hb and Hc both are equivalent to each other. non equivalent protons n= 3

Splitting pattern for Hb and Hc= 3+1 , Quartet

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Explanation:

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According to that for molecule 1 as shown on the second uploaded image

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Splitting pattern for Ha= 2+1 , Triplet

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Splitting pattern for Hb and Hc= 3+1 , Quartet

For Proton Hd, number of non equivalent protons n= 0

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Considering the second question for Molecule 2 as shown on the third uploaded image  

For Proton Ha, number of non equivalent protons n= 1

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For Proton Hc, number of non equivalent protons n= 3

Splitting pattern for Hc= 3+1=4 , Quartet

For Proton Hd, number of non equivalent protons n= 1

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Considering the third question

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The IUPAC name is Butan-2-ol

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