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kvv77 [185]
3 years ago
15

A triangle has a side length of 4 inches and an area of 18 square inches and a larger similar triangle has a corresponding side

length of 8 inches. Find the area of the larger tringle ?
...?
Mathematics
1 answer:
cricket20 [7]3 years ago
6 0
For this problem, we can use ratio since these triangle are said to be similar triangles. We calculate as follows:

L1/A1 = L2/A2
4/18 = 8/A2
2/9 = 8/A2
A2 = 36 square inches

The area of the larger triangle would be 36 square inches. Hope this answers the question. Have a nice day.
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In a right triangle, if sin 0 = 8/17 what is cos 0 explain?
Oliga [24]

Answer:

We have sin² x + cos² x =1 for all real x.

Therefore, sin² x = 1 – cos² x = 1 – (8/17)² = 1 – 64/289 = 225/289 = (15/17)².

However, remember that if x² = a², then x can be +a or –a.

Therefore, sin x can be either –15/17 or +15/17.

Everyone but Anirban so far has forgotten the negative solution.

Step-by-step explanation:

Given that sinθ=817 and cosθ<0 , we have: cosθ=−√1−sin2θ. cosθ=−√1−(817)2. cosθ=−√1−64289.

3 0
2 years ago
Indicate the equation of the given line in standard form. Write the answer in the equation box below.
denis-greek [22]

Answer:

x + 8y - 35 = 0.

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