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juin [17]
3 years ago
10

The graph shows the relationship between the number of pounds of pears purchase and the total cost of the pears.

Mathematics
1 answer:
Katarina [22]3 years ago
6 0
The answer is $1.75 because that’s what the graph shows per pound of pears
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Suppose you take the Medical College Admission Test (MCAT) and your score is the 32nd percentile. How do you interpret this resu
ExtremeBDS [4]

In Statistics, percentiles are a representation of the relative position of a particular value within a data set. For example, if your exam score is better than k% of the rest of the class. That means your exam score is at the kth percentile.

If your test score is at the 32nd percentile it can be interpreted as follows:

-Your test score is better than only 32 percent of the other scores recorded for the test.

-32 percent of the people who took the admission test have scores which are lower than yours.

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Step-by-step explanation:

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KiRa [710]

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3 0
3 years ago
Read 2 more answers
It is known that the population variance equals 484. With a .95 probability, the sample size that needs to be taken to estimate
Hitman42 [59]

Answer:

The minimum sample size is n = 75 so that the desired margin of error is 5 or less.                          

Step-by-step explanation:

We are given the following in the question:

Population variance = 484

Standard deviation =

\sigma^2 = 484\\\sigma =\sqrt{484} = 22

Confidence level = 0.95

Significance level = 0.05

Margin of error = 5

Formula:

Margin of error =

E = z\times \dfrac{\sigma}{\sqrt{n}}\\\\n = (\dfrac{z\times \sigma}{E})^2

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

Putting values, we get

E\leq 5\\\\1.96\times \dfrac{22}{\sqrt{n}} \leq 5\\\\\sqrt{n} \geq 1.96\times \dfrac{22}{5}\\\\n \geq (1.96\times \dfrac{22}{5})^2\\\\n \geq 74.373

Thus, the minimum sample size is n = 75 so that the desired margin of error is 5 or less.

3 0
3 years ago
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