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Wewaii [24]
3 years ago
6

A gray-scale digital camera with 1,000,000 pixels takes a picture (the picture is made of 1,000,000 parts and each part has a ce

rtain amount of gray). A histogram is made where the data is the amount of gray in each of these parts. The histogram looks bell-shaped with a mean of 125 gray levels and a standard deviation of 15.
Approximately how many pixels have a gray scale of between 110 and 140?

A. 30
B. 500,000
C. 680,000
D. 950,000
Mathematics
1 answer:
pashok25 [27]3 years ago
5 0
Let X be a random variable representing the mean gray scale of each pixel.
P(110 ≤ X ≤ 140) = P(X < 140) - P(X < 110) = P(z < (140 - 125)/15) - P(z < (110 - 125)/15) = P(z < 1) - P(z < -1) = P(z < 1) - [1 - P(z < 1)] = 2P(z < 1) - 1 = 2(0.84134) - 1 = 1.68268 - 1 = 0.68268

Number of pixels that have gray scale of between 110 and 140 = 0.68268 x 1000000 = 682680 = approximately 680,000
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Leokris [45]
<h3>Given :-</h3>

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<h3>To Find :-</h3>

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<h3>Solution :-</h3>

☼︎ <u>Radius of the Circle</u>;

<h3>Using Formula:</h3>

\\ \red\bigstar {\underline{\boxed{\color{springgreen}{\textsf{ \textbf{ \: Area \: of \: circle= \:  \: π \:  r \: ² \: }}}}}} \\\\

<u>Putting values in the formula;</u>

\\  \sf \implies \: Area \:  =  \: \pi \: r \:  ^{2}  \\

\\  \sf \implies \: 616 \:  =  \:\frac{22}{7}  \times  \: r \:  ^{2}  \\

\\  \sf \implies \: 616 \: \times  \: \frac{7}{22}  \:  =  \: \: r \:  ^{2}  \\

\\  \sf \implies \:  \: \frac{ \:  \: 4312 \:  \: }{22}  \:  =  \: \: r \:  ^{2}  \\

\\  \sf \implies \:  \:  \cancel{\frac{ \:  \: 4312 \:  \: }{22}  }\:  =  \: \: r \:  ^{2}  \\

\\  \sf \implies \:  \:   \: 196 \:  \: =  \: \: r \:  ^{2}  \\

\\  \sf \implies \:  \:r \:  ^{2}  =    \: 196 \:  \:   \: \:  \\

\\  \sf \implies \:  \:r \:   =    \sqrt{ \: 196 \:  } \\

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6 0
2 years ago
Read 2 more answers
Help please need done asap
vodka [1.7K]

Answer:

Answer is J

Step-by-step explanation:

Find one point: (1,0)

Substitute the numbers in the equations.

0+6= 3(1+1)

6= 3(2)

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8 0
3 years ago
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koban [17]

Answer:

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Step-by-step explanation:

Given

A = (-1,-2)

B = (2,4)

AP:BP = 1 : 2

Required

The locus of P

AP:BP = 1 : 2

Express as fraction

\frac{AP}{BP} = \frac{1}{2}

Cross multiply

2AP = BP

Calculate AP and BP using the following distance formula:

d = \sqrt{(x - x_1)^2 + (y - y_1)^2}

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Open brackets

4x^2 + 8x + 4y^2 +16y + 20 = x^2 - 4x + y^2 - 8y + 20

Collect like terms

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Divide through by 3

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3 0
3 years ago
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Answer:

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Step-by-step explanation:

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Shtirlitz [24]

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