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3 years ago

Which graph represents this system?

Mathematics

2 answers:

Vesnalui [34]3 years ago

6 0

Step-by-step explanation:

<u>Step 1: Find the correct option</u>

If you look at the attached photo, the option that fits those points is option B, therefore, the correct answer is B

Answer: Option B

<em>Look at the attachment:</em>

torisob [31]3 years ago

4 0

Answer:

On a coordinate plane, a line goes through (- 2, 0) and (0, - 3) and another goes through (0, 2) and (4, - 4).

(It's option 2)

Hope this helps!

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2.38 Baggage fees: An airline charges the following baggage fees: $25 for the first bag and $30 for the second. Suppose 54% of p

Anna71 [15]

The average baggage-related revenue per passenger is $16.30 per passenger.

<h3>Expected value</h3>

Expected value formula: x×p(x)

First step

No passenger=0×.54

No passenger=0

Second step

One checked luggage for first bag=.30×$25

One checked luggage for first bag=$7.50

Third step

Two piece for the first and second bag=.16×($25+$30)

Two piece for the first and second bag=.16×$55

Two piece for the first and second bag=$8.80

Last step

Expected value=$7.50+$8.80

Expected value=$16.30

Therefore the average baggage-related revenue per passenger is $16.30 per passenger.

Learn more about expected value here:brainly.com/question/24305645

#SPJ1

7 0

2 years ago

Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :