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ankoles [38]
2 years ago
10

If the homogeneity of variance assumption is violated in an independent groups t test, this means _________. the populations fro

m which the samples were drawn have different standard deviations you should use the sign test the sample sizes should be equal and N greater than 30 to use the t test the populations from which the samples were drawn have different standard deviations and the sample sizes should be equal and N greater than 30 to use the t test
Mathematics
1 answer:
Anit [1.1K]2 years ago
5 0

Answer:

the populations from which the samples were drawn have different standard deviations

Step-by-step explanation:

Given that the assumption of homogeneity of variance is the same as the assumption of the independent samples t-test which asserted that all comparison groups possess the same variance

Therefore, if the homogeneity of variance assumption is violated in an independent groups t-test, this means "the populations from which the samples were drawn have different standard deviations."

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18. Write an expression to represent the area of the shaded region in simplest form. Please help it's due tomorrow
IgorC [24]

Answer:

(x^2 + 2x - 21) sq units

Step-by-step explanation:

Area of the shaded region = Area of the larger rectangle - Area of smaller rectangle

Area of the larger region = x(x+2)

Area of the larger region =x^2 + 2x

Area of the smaller rectangle = 3 * 7

Area of the smaller rectangle = 21 sq. units

Area of the shaded region = x^2 + 2x - 21

Hence the required expression is (x^2 + 2x - 21) sq units

7 0
2 years ago
Find the area of an equilateral triangle with apothem 7 cm.
lbvjy [14]
So hmm check the picture below

using the 30-60-90 rule, we get that much.. .bear in mind, an equilateral triangle has all equal sides, and therefore, all equal angles, so each angle is 60°, run a median through it from the center, and you split it in half

\bf \textit{area of an equilateral triangle}\\\\
A=\cfrac{s^2\sqrt{3}}{4}\qquad 
\begin{cases}
s=\textit{length of one side}\\
----------\\
s=14\sqrt{3}
\end{cases}\implies A=\cfrac{(14\sqrt{3})^2\sqrt{3}}{4}
\\\\\\
A=\cfrac{14^2\cdot 3\sqrt{3}}{4}\implies A=\cfrac{588\sqrt{3}}{4}\implies A=147\sqrt{3}

8 0
3 years ago
What is equivalent to (x+8)(x+4)?<br>1.x^2+12x32<br>2.2x^2+10x+12<br>3.2x^2+12x+16<br>​
Elza [17]

Answer:

1. x^2+12x+32

Step-by-step explanation:

(x+8)(x+4)

x(x+4)+8(x+4)

x^2+4x+8x+32

x^2+12x+32

3 0
2 years ago
Read 2 more answers
Compare -5/6 _ -3/7 choose from 1) &gt; 2)
vfiekz [6]

Answer

1)<2) please put 5 stars

Step-by-step explanation

First you need to find the GCF of the donominators which are 6 and 7. The GCF is 42.

6*x=42. x=7 5*7=35. -35/42 is the first fraction.

7*y=42 y=6 3*6=18. -18/42 is the second fraction.

-35/42 would be bigger but since it is negative, it is smaller.

8 0
3 years ago
Read 2 more answers
Pls solve the simultaneous equation in the attachment.
siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

\frac{x}{2}-\frac{y}{5}=1 ----> equation A

y-\frac{x}{3}=8 ----> equation B

Multiply equation A by 10 both sides to remove the fractions

5x-2y=10 ----> equation C

isolate the variable y in equation B

y=\frac{x}{3}+8 ----> equation D

we have the system of equations

5x-2y=10 ----> equation C

y=\frac{x}{3}+8 ----> equation D

Solve the system by substitution

substitute equation D in equation C

5x-2(\frac{x}{3}+8)=10

solve for x

5x-\frac{2x}{3}-16=10

Multiply by 3 both sides

15x-2x-48=30

15x-2x=48+30

Combine like terms

13x=78

x=6

<em>Find the value of y</em>

y=\frac{x}{3}+8

y=\frac{6}{3}+8

y=10

The solution is the ordered pair (6,10)

Part b) we have

xy=21 ---> equation A

x+5y=22 ----> equation B

isolate the variable x in the equation B

x=22-5y ----> equation C

substitute equation C in equation A

(22-5y)y=21

solve for y

22y-5y^2=21

5y^2-22y+21=0

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

<em>Find the values of x</em>

For y=1.4

x=22-5(1.4)=15

For y=3

x=22-5(3)=7

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

3 0
3 years ago
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