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jekas [21]
3 years ago
11

Trinomial in factored form 5y^2-y-18

Mathematics
2 answers:
Inessa05 [86]3 years ago
8 0

Answer:

Step-by-step explanation:

(5y + 9)(y - 2) is the solution

5y^2 - 10y + 9y - 18

Liono4ka [1.6K]3 years ago
5 0

Answer:

(5y+9)(y-2)  i think

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Bisects ∠EDG. Find the value of x
True [87]

Answer:

where is the question? please attatch the angle

6 0
3 years ago
Write the number shown in standard notation. 1.02 x 10 First Correct answer gets Brainliest
SIZIF [17.4K]

Answer:

1.02×10¹ = 10.2

Step-by-step explanation:

We have given a number in scientific notation as follows 1.02×10¹

We need to convert it into standard notation.

1 is in ones place, 0 is in tenths place and 2 is in hundredths place.

1.02\times 10^1=\dfrac{102}{100}\times 10\\\\=\dfrac{102}{10}\\\\=10.2

So, the standard notation of 1.02×10¹ is 10.2

7 0
3 years ago
Before every​ flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the ai
ollegr [7]

Answer:

The probability that the aircraft  is  overload = 0.9999

Yes , The pilot has to be take strict action .

Step-by-step explanation:

P.S - The exact question is -

Given - Before every​ flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the aircraft. The aircraft can carry 37 ​passengers, and a flight has fuel and baggage that allows for a total passenger load of 6,216 lb. The pilot sees that the plane is full and all passengers are men. The aircraft will be overloaded if the mean weight of the passengers is greater than 6216/37 = 168 lb. Assume that weight of men are normally distributed with a mean of 182.7 lb and a standard deviation of 39.6.

To find - What is the probability that the aircraft is​ overloaded ?

         Should the pilot take any action to correct for an overloaded aircraft ?

Proof -

Given that,

Mean, μ = 182.7

Standard Deviation, σ = 39.6

Now,

Let X be the Weight of the men

Now,

Probability that the aircraft is loaded be

P(X > 168 ) = P(\frac{x - \mu}{\sigma} > \frac{168 - \mu}{\sigma} )

                 = P( z > \frac{168 - 182.7}{39.6} )

                 = P( z > -0.371)

                 = 1 - P ( z ≤ -0.371 )

                 = 1 - P( z > 0.371)

                 = 1 - 0.00010363

                 = 0.9999

⇒P(X > 168) = 0.9999

As the probability of weight overload = 0.9999

So, The pilot has to be take strict action .

5 0
2 years ago
I need to know the answer and how to solve this
AURORKA [14]

Answer:

135

Step-by-step explanation:

subtract 180 by 45 since a line is 180, that is what you get for the angle that is adjacent to angle 2, there is a rule if it is adjacent, they equal each other. thus, angle 2 is 135

5 0
2 years ago
Which of the following has a solution set of {x | x = 0}?
Burka [1]
It is B 
(x+1<1)this mark(x+1>1)
8 0
3 years ago
Read 2 more answers
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