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3 years ago

Trinomial in factored form 5y^2-y-18

Mathematics

2 answers:

Inessa05 [86]3 years ago

8 0

Answer:

Step-by-step explanation:

(5y + 9)(y - 2) is the solution

5y^2 - 10y + 9y - 18

Liono4ka [1.6K]3 years ago

5 0

Answer:

(5y+9)(y-2) i think

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What kind of inequality is this

Nina [5.8K]

There is literally no question

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3 years ago

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A right triangle has an area of 18 square inches if the triangle is not an isosceles triangle what are all the possible lengths

adoni [48]

Answer:

1 inch by 36 inches

2 inches by 18 inches

3 inches by 12 inches

4 inches by 9 inches

Step-by-step explanation:

A right triangle has an area of 18 square inches

The triangle is not an isosceles triangle

The area of a right triangle is given by; $\frac{1}{2}$ × base(b) × height(h)

In our case, the base and the height of the triangle are known as legs

So, $\frac{1}{2}$ × b × h = 18 square inches

b × h = 18 × 2 = 36 square inches

The possible factors of 36 (or lengths of the legs) that could give an area of 18 square inches are:

Base by Height:

1 inch by 36 inches

2 inches by 18 inches

3 inches by 12 inches

4 inches by 9 inches

7 0

3 years ago

9/10-3/14_____<br><br> Simplest form

Lera25 [3.4K]

10=2×5 and 14=2×7 so least common denominator will be 2×5×7=70
9/10=63/70
3/14=15/70
So 63/70-15/70=48/70=24/35

3 0

4 years ago

The ratio of the number of boys to the number of girls in a choir is 5 to 4. There are 60 girls in the choir. How many boys are

Korvikt [17]

Let the number of boys and the number of girls be 5x and 4x

Number of girls = 4x = 60

x = 15

Number of boys = 5x

= 5× 15

= 75 boys

5 0

3 years ago

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A vertical lamppost of height 6 m is at P When Sam stands at the point A. the shadow formed is 2.1 m long. When Sam stands at th

Damm [24]

Step-by-step explanation:

triangle ADA' and OPA' are similar so, using property of similar triangles :

6/AD = (13.3+3.6-PB'+2.1)/2.1

{A'P = 13.3 +3.6 - PB' + 2.1}

6/AD = (16.9-PB'+2.1)/2.1

6/AD = (19-PB')/2.1 - EQN I

As we know, AD = BC as both of them are Sam's height (constant)

triangle OPB' and BCB' are similar so, using property of similar triangles:

6/BC = PB'/3.6

OR, 6/AD = PB'/3.6 (AD = BC) - EQN II

Now,

comparing EQN I AND II we get :

(19-PB')/2.1 = PB'/3.6

or, 68.4 - 3.6PB' = 2.1PB'

or, 68.4 = 5.7PB'

so, PB' = 12 m

Now, as we know,

6/BC = PB'/3.6

OR, 6/BC = 12/3.6

OR, (6×3.6)/12 = BC

So, the height of Sam is 1.8 m.

tanA' = AD/AA'

<A' = tan‐¹(1.8/2.1)

<B' = tan‐¹(1.8/3.6)

Now,

<A'OB' = 180 - tan‐¹(1.8/2.1) - tan‐¹(1.8/3.6)

<A'OB' = 112.833

7 0

2 years ago