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Afina-wow [57]
3 years ago
8

Town A and town B calculated the number of dogs in each town based on the average number of dogs per neighborhood. The graph bel

ow represents the number of dogs in town A. The equation below represents the number of dogs, y, in town B, where x represents the number of neighborhoods in the town.
y = 10x
Which town has the greater average number of dogs per neighborhood?
A. There is not enough information to determine the average number of dogs per neighborhood.
B. Town A and town B have the same average number of dogs per neighborhood.
C. Town A has the greater average number of dogs per neighborhood.
D. Town B has the greater average number of dogs per neighborhood.

Mathematics
1 answer:
MAXImum [283]3 years ago
7 0

Answer:

C. Town A has the greater average number of dogs per neighborhood.

Step-by-step explanation:

First, find Town A's average number of dogs per neighborhood. Since the graph is a straight line, you can find the number of dogs per neighborhood by dividing a given y-value by its x-value counterpart:

(4,60)

60 dogs / 4 neighborhoods

<u>15 dogs / neighborhood.</u>

Now, we must find the average number of dogs per neighborhood in Town B. Since the equation is y = 10x, where x is the number of neighborhoods, in 1 neighborhood, there are 10 dogs:

<u>10 dogs / neighborhood.</u>

Finally, compare the two values:

15 > 10

<u>C. Town A has the greater average number of dogs per neighborhood.</u>

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Step-by-step explanation:

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\bold{CORRECT}\\\\\dfrac{x}{\frac{4}{27}}=\dfrac{2}{3}\qquad\text{multiply both sides by}\ \dfrac{4}{27}\\\\x=\dfrac{2}{3}\cdot\dfrac{4}{27}\\\\x=\dfrac{8}{81}

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