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3 years ago

Can someone help me

Mathematics

1 answer:

rodikova [14]3 years ago

3 0

Try this explanation:

Note, in the 1st row given '9x', in the 2d one - '9(0)', then it means the substitution '0' instead of 'x'. In other words <u>x=0</u> !

answer: x-intercept is '0', y-intercept is '12'

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1000 grams decreased by 94%

gregori [183]

$subtract\ 94\%\ of\ 1000\ from\ 1000\\\\1000-94\%*10000=1000-0.94*1000=1000-940=60\\\\
1000\ grams\ decreased\ by\ 94\%\ is\ 60.$

3 0

3 years ago

A number greater than -5

Serggg [28]

Answer:

Hi there!

Your answers are:

1) x> 5

Some numbers that would fit this equation are 6, 7, 8, etc!

2) x<= 30

Some numbers that would fit this are 30, 29, 28, etc!

3) x>= 17

Some numbers that would fit this equation are 17, 18, 19, etc!

4) x>= 90

Some numbers that would fit this are 90, 91, 92, etc!

Hope this helps!

5 0

3 years ago

The area of a triangle is 30 square centimeters and its base is 10 cm. What is the height in cm of the triangle

Vesnalui [34]

Answer:

The height of the triangle is $6$ cm.

Step-by-step explanation:

----------------------------------------

The formula for solving the area of a triangle is $A=\frac{1}{2}bh$ where $b$ stands for base and $h$ stands for height.

Let's substitute 30 $cm^2$ for the area and 10 for the base.

$30=\frac{1}{2} (10)h$

-------------------->>>>

Now, let's solve to find the height.

$30=\frac{1}{2}(10)h$

Multiply $\frac{1}{2}$ times $10$

$30=5h$

Divide both sides by 5.

$6=h$

-----------------------------------------

Hope this is helpful.

4 0

3 years ago

compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.

Nina [5.8K]

$\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})$

We have been given two vectors $\vec{a}$ and $\vec{b}$ , we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of $\vec{b}$ onto $\vec{a}$ means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

The scalar projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

#SPJ4

3 0

1 year ago

Can y'all help me with this please

asambeis [7]

12 times 35 times 28= 980..... im not sure

5 0

3 years ago