Answer:
68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds
This is the pvalue of Z when X = 8.6 subtracted by the pvalue of Z when X = 6.4. So
X = 8.6



has a pvalue of 0.8413
X = 6.4



has a pvalue of 0.1587
0.8413 - 0.1587 = 0.6826
68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds
Answer:
33, 39, 45, 51
Step-by-step explanation:
The general term of an arithmetic sequence is given by the formula ...
an = a1 + d(n-1) . . . where a1 is the first term and d is the common difference
Comparing this formula to the one you are given, you see that ...
a1 = 33, d = 6
This means the first term is 33, and each successive term is 6 more than the previous one. The first 4 terms are ...
33, 39, 45, 51
Answer:
A) x = 2, x = 7
Step-by-step explanation:
x^2 + 14 = 9x
Subtract 9x from each side
x^2-9x + 14 = 9x-9x
x^2-9x + 14 = 0
What 2 numbers multiply to 14 and add to -9
-7*-2 = 14
-7+-2 = -9
(x-7)(x-2) = 0
Using the zero product property
x-7 = 0 x-2 =0
x=7 x=2
Hopes this helps:
Answer: 48