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Allisa [31]
3 years ago
8

Which angle?

Mathematics
1 answer:
kirill [66]3 years ago
8 0

Answer:

Perpendicular

Step-by-step explanation:

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From an urn containing 3 white and 2 black balls, two balls are drawn one after the other without replacement. What is the proba
Marina86 [1]

Answer:

There is a 3/5 chance of the first ball being white, and a 3/10 chance the second one is black.

Step-by-step explanation:

There are 5 balls, of which 3 are white, so you have a 3/5 chance of the first one being white. Then you have 2 white and 2 black balls. There is a 2/4 chance of picking a black ball. Multiply 3/5 and 2/4 to get 6/20, or 3/10 for choosing a white ball then a black ball.

6 0
3 years ago
WILL GIVE BRAINLIEST TO FIRST PERSON WHO ACTUALLY TRIES!!!
Ivenika [448]

Answer:

Around 8.8

Step-by-step explanation:

This problem requires the Pythagorean Theorem. We are given the hypotenuse and a leg, so we can plug in what we know.

{x^2+2^2}=9^2 \\{4+x^2}=81 \\x^2=77\\\sqrt{x^2}=77\\x=\sqrt{77}\\x=8.8, approximately

5 0
3 years ago
Solve the following system of equations using the substitution method.
BartSMP [9]

Answer:

B

Step-by-step explanation:

First label the equations.

6x +3y= 18 -----(1)

y= -2x +5 -----(2)

subst. (2) into (1):

6x +3(-2x +5)= 18

6x +3(-2x) +3(5)= 18 (expand)

6x -6x +15= 18

15= 18 (simplify)

(reject)

There is no solution.

<u>Further explanation</u><u>:</u>

If I rewrite the first equation into the form of y=mx+c, I would get

6x +3y=18

3y= 18 -6x (bring y term to one side)

y= 6- 2x (÷3 throughout)

y= -2x +6

Notice that the gradients of both lines are equal ( -2). This implies that they are parallel to each other and will never meet. Hence there are no solutions.

3 0
3 years ago
Find the distance between a point (– 2, 3 – 4) and its image on the plane x+y+z=3 measured across a line (x + 2)/3 = (2y + 3)/4
dimaraw [331]

Answer:

Distance of the point from its image = 8.56 units

Step-by-step explanation:

Given,

Co-ordinates of point is (-2, 3,-4)

Let's say

x_1\ =\ -2

y_1\ =\ 3

z_1\ =\ -4

Distance is measure across the line

\dfrac{x+2}{3}\ =\ \dfrac{2y+3}{4}\ =\ \dfrac{3z+4}{5}

So, we can write

\dfrac{x-x_1+2}{3}\ =\ \dfrac{2(y-y_1)+3}{4}\ =\ \dfrac{3(z-z_1)+4}{5}\ =\ k

=>\ \dfrac{x-(-2)+2}{3}\ =\ \dfrac{2(y-3)+3}{4}\ =\ \dfrac{3(z-(-4))+4}{5}\ =\ k

=>\ \dfrac{x+4}{3}\ =\ \dfrac{2y-3}{4}\ =\ \dfrac{3z+16}{5}\ =\ k

=>\ x\ =\ 3k-4,\ y\ =\ \dfrac{4k+3}{2},\ z\ =\ \dfrac{5k-16}{3}

Since, the equation of plane is given by

x+y+z=3

The point which intersect the point will satisfy the equation of plane.

So, we can write

3k-4+\dfrac{4k+3}{2}+\dfrac{5k-16}{3}\ =\ 3

=>6(3k-4)+3(4k+3)+2(5k-16)\ =\ 18

=>18k-24+12k+9+10k-32\ =\ 18

=>\ k\ =\dfrac{13}{8}

So,

x\ =\ 3k-4

   =\ 3\times \dfrac{13}{8}-4

   =\ \dfrac{7}{4}

y\ =\ \dfrac{4k+3}{2}

   =\ \dfrac{4\times \dfrac{13}{8}+3}{2}

   =\ \dfrac{19}{4}

z\ =\ \dfrac{5k-16}{3}

  =\ \dfrac{5\times \dfrac{13}{8}-16}{3}

   =\ \dfrac{-21}{8}

Now, the distance of point from the plane is given by,

d\ =\ \sqrt{(x-x_1)^2+(y-y_1)^2+(z-z_1)^2}

   =\ \sqrt{(-2-\dfrac{7}{4})^2+(3-\dfrac{19}{4})^2+(-4+\dfrac{21}{8})^2}

   =\ \sqrt{(\dfrac{-15}{4})^2+(\dfrac{-7}{4})^2+(\dfrac{9}{8})^2}

   =\ \sqrt{\dfrac{225}{16}+\dfrac{49}{16}+\dfrac{81}{64}}

   =\ \sqrt{\dfrac{1177}{64}}

   =\ 4.28

So, the distance of the point from its image can be given by,

D = 2d = 2 x 4.28

            = 8.56 unit

So, the distance of a point from it's image is 8.56 units.

4 0
3 years ago
If X = {−1, 0, 2} and Y = {1, 2, 5}, find X ∪ Y.
Irina18 [472]

yo sup??

as mentioned earlier XUY is simply the summation of all the unique elements of X and Y

S=XUY

={-1,0,1,2,5}

Therefore your answer is option 1 ie

1.{-1,0,1,2,5}

Hope this helps.

5 0
4 years ago
Read 2 more answers
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