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fomenos
3 years ago
7

What is the highest common factor of 12 and 47​

Mathematics
1 answer:
icang [17]3 years ago
8 0
The factors of 12 are: 1, 2, 3, 4, 6, 12

The factors of 47 are: 1, 47

Then the greatest common factor is 1.


Hope this helps *smiles*
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A line includes the points (4, 8) and (3, 5). What is its equation in slope-intercept form? Write your answer using integers, pr
stich3 [128]

Answer:

A line includes the points (4, 8) and (3, 5) whose equation in slope-intercept form will be :

y=3x-4

Step-by-step explanation:

The point slope form: (x_1,y_1) and(x_2,y_2)

(y-y_1)=m(x-x_1)

where : m = Slope of the line

m=\frac{y_2-y_1}{x_2-x_1}

A line includes the points (4, 8) and (3, 5).The equation of the line will be:

m=\frac{5-8}{3-4}=3

(y-8)=3\times (x-4)

y-8=3x-12

y=3x-4

(y=mx+c), where c is intercept at y axis.

The above equation represents slope-intercept form of the line.

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3 years ago
Shelley's Cupcakes recently sold 8 cupcakes, of which 4 were coconut cupcakes. Considering this data, how many of the next 20 cu
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Answer:

10 coconut cupcakes.

Step-by-step explanation:

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3 years ago
HURRYYYWhat is the value of the expression (5)3?
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5x6=25x5=125 (125) I think it’s correct
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Cone W has a radius of 8 cm and a height of 5 cm. Square pyramid X has the same base area and height as cone W. Paul and Manuel
sergij07 [2.7K]

This question is incomplete because it lacks the appropriate attachment containing the argument of Paul and Manuel

Kindly find attached the appropriate attachment necessary to solve this question.

The attachment was sourced online

Answer:

a) Paul's argument is correct, Manuel used the wrong formula to find the volume of square pyramid X

Step-by-step explanation:

From the above question, we are given two shapes: Cone W and Square Pyramid

Cone W: Radius = 8cm, Height = 5cm

Volume of a Cone = 1/3 πr²h

Where π = 3.14

Volume of Cone X = 1/3 × 3.14 × 8² × 5

= 334.93cm³

For Square pyramid X

Volume = 1/3 × Base Area × Height

Base Area of Cone W = Base Area of square pyramid X = πr²

Where π = 3.14

Base area = 3.14 × 8² = 200.96cm²

Height of Square pyramid X = Height of Cone W = 5cm

Volume of Square pyramid = 1/3 ×200.96cm² × 5cm

= 334.93cm³

Therefore, from my above calculation and compared with the arguments of Paul and Manuel, Option a) "Paul's argument is correct, Manuel used the wrong formula to find the volume of square pyramid X" is the correct option.

The reason why is because the correct formula for the volume of a square pyramid = 1/3 × Base area × Height

This was the formula Paul used.

Manuel on the other hand used the formula: Base Area × Height to find the volume of cone W. This formula is wrong.

Option a, is the correct answer.

4 0
3 years ago
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