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katrin2010 [14]
3 years ago
6

The sum of three numbers is 62. The second number is equal to the first number diminished by 4. The third number is four times t

he first. What are the numbers?
Which three expressions could be used to represent the numbers?

Mathematics
2 answers:
alexdok [17]3 years ago
3 0
Let the three numbers be x, y and z respectively, then
x + y + z = 62 . . . (1)
y = x - 4 . . . (2)
z = 4x . . . (3)

The above three expressions could be used to represent the numbers.

Solving the three equations, putting (2) and (3) into (1) gives
x + x - 4 + 4x = 62
6x - 4 = 62
6x = 62 + 4 = 66
x = 66/6 = 11
x = 11.
y = 11 - 4 = 7
z = 4(11) = 44

x = 11, y = 7, z = 44.
blsea [12.9K]3 years ago
3 0
I hope this helps you

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<u>Now we know that our equation is y = 3(x - 1)^2 - 9.</u>

Now to solve for the zeros (x-intercepts). Set y to 0 and add 9 to both sides of the equation: 9=3(x-1)^2

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Next, square root both sides: \pm\sqrt{3}=x-1

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s2008m [1.1K]

3 + 0.75x = 5.25 - 0.25x

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The product of two even numbers is even.

 

Let m and n be any integers so that 2m and 2k are two even numbers.

The product is 2m(2k) = 2(2mk), which is even.

 

 

Things to think about:

Why didn’t I just show you by using any two even numbers like the number 4 and the number 26?

Why did I change from "m" to "k" ? Are they really different numbers or could they be the same?

Why did I specifically say that m and k were integers?

 

The product of two odd numbers is an odd number.

Let m and k be any integers. This means that 2m+1 and 2k+1 are odd numbers.

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