Answer:
Mean, Mode, Median, Range, Standard Deviation.
Step-by-step explanation:
The completed sentences are as follows -
- The arithmetic average of a distribution of scores is the Mean
- The score that shows up most often is the Mode
- The score right in the middle of a distribution is the Median
- We determine how much scores vary around the average in a way that includes information about the Range of scores by using the Standard Deviation
Answer:
C. x = 3, y = -6
Step-by-step explanation:
You can divide the second equation by 2. Then you have ...
x +2y = -9
This gives you a couple of choices for solution. The x-coefficients match, so subtracting one equation from the other eliminates x:
(x +2y) -(x -2y) = (-9) -(15)
4y = -24 ⇒ y = -6
Adding the two equations eliminates y:
(x -2y) +(x +2y) = (15) +(-9)
2x = 6 ⇒ x = 3
The solution is (x, y) = (3, -6).
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<em>Additional comment</em>
I find it quick and easy to use a graphing calculator to find the solution. Many graphing calculators also make it simple to solve systems of equations in matrix form. Either way, you can obtain a solution in little more than the time it takes to enter the equations (or their coefficients).
Answer:
x=3
Step-by-step explanation:
You have to look at the line(axis of symmetry) and determine what number it is it going thought, and whether it is going through the x or y axis.
In this case the axis of symmetry is going through the x axis and 3, therefore the answer is x=3.
Hope this helps!
Answer:
p=2
Step-by-step explanation:
-7p = -3p - 8
Add 3p to each side
-7p+3p = -3p+3p - 8
-4p = -8
Divide each side by -4
-4p/-4 = -8/-4
p = 2
Answer:
The answer in the procedure
Step-by-step explanation:
Let
A1 ------> the area of the first square painting
A2 ----> the area of the second square painting
D -----> the difference of the areas
we have


case 1) The area of the second square painting is greater than the area of the first square painting
The difference of the area of the paintings is equal to subtract the area of the first square painting from the area of the second square painting
D=A2-A1


case 2) The area of the first square painting is greater than the area of the second square painting
The difference of the area of the paintings is equal to subtract the area of the second square painting from the area of the first square painting
D=A1-A2

