“The breaking distance is directly proportional to the square of its speed”
Using your variables, this means: d = k•b^2
k here is some unknown (and for this question irrelevant) number.
Now if b (the speed) is increased by 200%, then your new speed is b+2b = 3b. The 2b is the 200% increase.
Throw 3b into the first equation we have the new d as:
d = k • (3b)^2
Simplifying this, you have d = k•9b or d=9kb
This means the new braking distance is 9 times the original braking distance.
Answer: 61.2?
Step-by-step explanation:
Answer:
Using the combination formula:
Number of combination of r object chosen from the total object i.e n is given by:

As per the statement:
4 candy bars be chosen from a store that sells 30 candy bars
Number of candy bars chosen from a store that sells 30 candy bars(r)= 4
and
Total candy bars(n) = 30
then substitute in the given formula we have;

⇒
⇒
Simplify:
⇒
therefore, 27,405 ways can 4 candy bars be chosen from a store that sells 30 candy bars