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Vilka [71]
3 years ago
5

6000 divided by 30 simplified what is it

Mathematics
1 answer:
Katena32 [7]3 years ago
5 0

Answer:

200

Step-by-step explanation:

6,000 divided by 30 is 200

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love history [14]

Answer:

10 A. Quadrent 2

10 B. Quadrent 3

Step-by-step explanation:

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5 0
3 years ago
Function c is defined by the equation c(n) = 50 + 4n. It gives the monthly cost, in dollars, of visiting a gym as a function of
vampirchik [111]

Answer:

78 dollars

Step-by-step explanation:

Function c is defined by the equation c(n) = 50 + 4n. It gives the monthly cost, in dollars, of visiting a gym as a function of the number of visits, n. Find the value of c(7).

Given:

c(n) = 50 + 4n

Where,

c = monthly cost of visiting a gym

n = number of visits

Find the value of c(7)

That is, when n = 7

c(n) = 50 + 4n

c(7) = 50 + 4(7)

= 50 + 28

= 78

c(7) = 78 dollars

8 0
3 years ago
Which is an equivalent form of the first equation that when added to second equation eliminates the x terms? 4/5 x-3/5y=18
Fittoniya [83]

Answer:

-8x + 6y = -180

Step-by-step explanation:

Given

\frac{4}{5} x-\frac{3}{5}y=18

8x + 12y = 11

Required

Equivalent form of the first equation that eliminates x when added to the second

To do this, we simply make the coefficients of x to be opposite in both equations.

In the second equation, the coefficient of x is 8.

So, we need to make the coefficient of x -8, in the first equation.

\frac{4}{5} x-\frac{3}{5}y=18

Multiply by -10

-10 * [\frac{4}{5} x-\frac{3}{5}y=18]

\frac{-40}{5} x+\frac{30}{5}y=-180

-8x + 6y = -180

<em>When this is added to the first equation, the x terms becomes eliminated</em>

6 0
3 years ago
A scholarship would be an example of a cash ____ .
zavuch27 [327]
The answer would be 1)
8 0
4 years ago
Read 2 more answers
The heights of a certain population of corn plants follow a normal distribution with mean 145 cm and stan- dard deviation 22 cm
Firdavs [7]

Answer with explanation:

Given : The heights of a certain population of corn plants follow a normal distribution with mean \mu=145\ cm and standard deviation \sigma=22\ cm

a) Using formula z=\dfrac{x-\mu}{\sigma}, the z-value corresponds to x= 135 will be

z=\dfrac{135-145}{22}\approx-0.45

At x= 155, z=\dfrac{155-145}{22}\approx0.45

The probability that plants are between 135 and 155 cm tall :-

P(-0.45

Hence, 34.73% of the plants are between 135 and 155 cm tall.

b) Sample size : n= 16

Using formula z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}, the z-value corresponds to x= 135 will be

z=\dfrac{135-145}{22}{\sqrt{16}}\approx-1.82

At x= 155, z=\dfrac{155-145}{22}{\sqrt{16}}\approx1.82

The probability that plants are between 135 and 155 cm tall :-

P(-1.82

Hence,The percentage of the samples would the sample mean height be between 135 and 155 cm.= 93.12%  

4 0
4 years ago
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