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stealth61 [152]
3 years ago
8

Solve for a. a+(−4)=−13

Mathematics
2 answers:
dangina [55]3 years ago
6 0
In your equation:  a+(-4)=-13
you then add four to each side, 
so a= negative 13 plus 4
so a=  -9
barxatty [35]3 years ago
5 0

Answer:

in your equation:  a+(-4)=-13

you then add four to each side,

so a= negative 13 plus 4

so a=  -9

Step-by-step explanation:

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30 POINTS By looking at the intercepts, which linear function does the graph represent?
larisa86 [58]

C. f(x)=2/3x-2

<h2>Explanation:</h2>

Looking at the graph we realize that the y-intercept is given by:

b=-2

The Slope-intercept form of the equation of a line is given by:

y=mx+b

So, our equation becomes:

y=mx-2

So the only option that matches a negative y-intercept is C. Let's see that the slope m=2/3. Look at the y-intercept, if you increase x by 3 units, then y increases by 2 units and goes from x=-2 to x=0. In other words:

Change \ in \ x=\Delta x=3 \\ \\ Change \ in \ y=\Delta y=2 \\ \\ \\ m=\frac{\Delta y}{\Delta x}=\frac{2}{3}

<h2>Learn more:</h2>

Writing linear equations: brainly.com/question/12169569

#LearnWithBrainly

7 0
3 years ago
PLS HELP BRAINLIEST
laiz [17]

Answer:

a) AB = 17 m

b) AC = 20.8 m

Step-by-step explanation:

Pythagorean theorem

a^2 + b^2 = c^2

a)

AB^2 = (26-11)^2 + 8^2

AB^2 = 15^2 + 8^2

AB^2 =  225 + 64

AB^2 = 289

AB = 17 m

b)

AC^2 = AB^2 + BC^2

AC^2 = 17^2 + 12^2

AC^2 =289 + 144

AC^2 = 433

AC = 20.8 m

7 0
3 years ago
Consider the function f(x)=−3/4 x+1.
jenyasd209 [6]
-(3/4) (12)+1 = -9+1=. -8
7 0
2 years ago
If JK has endpoints J(-2, 3) and K(6, 5), and LN has endpoints L(0, 7) and N (4, 1), then JK and LN have the same midpoint
NISA [10]
Given:
J (-2,3), K(6,5), L(0,7) and N(4,1).

Note that the midpoint of a line connecting the two points (x₁,y₁) and (x₂,y₂) is
(x,y), where
x = (x₁ + x₂)/2
y = (y₁ + y₂)/2

Calculate the midpoint for line JK.
x = (-2 + 6)/2 = 2
y = (3 + 5)/2 = 4
The midpoint of line JK is (2, 4).

Calculate the midpoint of line LN.
x = (0 + 4)/2 = 2
y = (7 + 1/2 = 4
The midpoint of line LN is (2, 4).

The midpoints for lines JK and LN are the same.

Answer:
Lines JK and LN have the same midpoint.
8 0
3 years ago
When the sun shines at a 30° angle to the ground, Manuel’s shadow is 109 in. long. To the nearest inch, how tall is Manuel?
leva [86]

Answer:

63 inches

Step-by-step explanation:

Given: Manuel’s shadow is 109 inches when the sun shines at a 30° angle to the ground.

To find: Height of Manuel

Solution:

Let AB denotes height of Manuel and BC denotes shadow of Manuel.

\tan  C=\frac{side \,\,opposite \,\,to\,\, the\,\, angle}{side \,\,adjacent \,\,to\,\, the\,\, angle}

Side opposite to \angle C = AB

Side adjacent to \angle C=  BC

\angle C=30^{\circ}

\tan 30^{\circ}=\frac{AB}{BC}\\\frac{1}{\sqrt{3}}=\frac{AB}{109}\\AB=\frac{109}{\sqrt{3}}=62.93\approx 63\,\,inches

7 0
3 years ago
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