Add 1/10 and 8/100. what is the sum?

Help I need help determining

Alekssandra [29.7K]

Answer:

Only A and C are functions.

Step-by-step explanation:

X-values cannot repeat in the case of functions.

7 0

3 years ago

A square has a perimeter given by the expression 16x+32y. Write an expression for the length of one side of the square.

Lemur [1.5K]

A square has 4 equal sides which make up the perimeter.

Therefore the length of one side = (16x + 32y) / 4 = 4x + 8y Answer

8 0

3 years ago

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At the end of the month mr copley has $1473.61 in is checking account his checkbook showed the following transaction if made mad

ycow [4]

Total balance in Mr. Copley at the end of the month = $1473.61.

Initial deposite = $75 (not shown in his checkbook).

Let us assume his balance at the beginning of the month = x.

Total balance at the end of the month = The balance at the beginning of the month + total deposite.

$1473.61 = x + 75.

Subtracting 75 from both sides, we get

1473.61 -75 = x + 75 -75.

1398.61 = x.

Therefore, his balance at the beginning of the month was $1398.61.

7 0

4 years ago

Let f = (ax + by + 4z) i + (x + cz) j + (9y + mx) k where a, b,c, and m are constants.

Tom [10]

Let $\mathcal R$ be an arbitrary closed region with boundary the surface $\mathcal S$ . By the divergence theorem,

$\displaysytle\iint_{\mathcal S}\mathbf f(x,y,z)\cdot\mathrm d\mathbf S=\iiint_{\mathcal R}\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV$

We have

$\nabla\cdot\mathbf f(x,y,z)=\dfrac{\partial(ax+by+4z)}{\partial x}+\dfrac{\partial(x+cz)}{\partial y}+\dfrac{\partial(9y+mx)}{\partial z}=a$

so that the flux satisfies

$\displaystyle a\iiint_{\mathcal R}\mathrm dV=0$

We're assuming $\mathcal R$ is a closed region, and the integral above is its volume, which must be positive. This means we must have $a=0$ .

7 0

3 years ago

Jackson purchased some power tools totaling $1,543 using a six month deferred payment plan with an interest rate of 23.76%. He d

skad [1K]

Suppose he makes the payment with two equal annual instalments, the present value of the amount he is owing is $1,543 , the interest rate is 23.76% = 0.2376.

The amount of payment he makes in two of the periodic payments is given by:

$PV = P\left( \frac{1-(1+r)^{-n}}{r} \right) \\ \\ \Rightarrow1,543=P\left( \frac{1-(1+0.2376)^{-2}}{0.2376} \right) \\ \\ =P\left( \frac{1-(1.2376)^{-2}}{0.2376} \right)=P\left( \frac{1-0.6529}{0.2376} \right) \\ \\ =P\left( \frac{0.3471}{0.2376} \right)=1.4609P \\ \\ \Rightarrow P= \frac{1,543}{1.4609} =1,056.20$

Therefore, in 2 years, the amount he has paid for the tools is 2(1,056.20) = 2,112.40

4 0

4 years ago