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2 years ago

6

MODELING REAL LIFE The table shows the profit y for recycling x pounds of aluminum. Find the profit for recycling 75 pounds of a

luminum. Aluminum (lb), x 10 20 30 40 Profit, y $4.50 $9.00 $13.50 $18.00

1 answer:

True [87]2 years ago

8 0

Answer: 33.75

Step-by-step explanation:

It’s right

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Approximately 10% of all people are left-handed. Consider a grouping of fifteen people.

vaieri [72.5K]

1.5 but you can’t get half a person

8 0

3 years ago

We form a committee of 8 people, to be chosen from 15 women and 12 men. (a) How many possible committee can be formed

eimsori [14]

Using the combination formula, it is found that 2,220,075 committees can be formed.

The order in which the people are chosen is not important, hence, the <em>combination formula</em> is used to solve this question.

<h3>Combination formula: </h3>

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by:

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this problem, 8 people are chosen from a set of 12 + 15 = 27, hence:

$C_{27,8} = \frac{27!}{8!19!} = 2220075$

2,220,075 committees can be formed.

To learn more about the combination formula, you can take a look at brainly.com/question/25821700

3 0

2 years ago

3x +12 =90 what is x

castortr0y [4]

Answer:

x=26

Step-by-step explanation:

3x +12 =90

subtract 12 from each side

3x=78

divide 3 from each side

x=26

3 0

2 years ago

Read 2 more answers

Solve 73 make sure to also define the limits in the parts a and b

Aleks04 [339]

73.

$f(x)=\frac{3x^4+3x^3-36x^2}{x^4-25x^2+144}$

a)

$\lim_{x\to\infty}f(x)=\lim_{x\to\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3$ $\lim_{x\to-\infty}f(x)=\lim_{x\to-\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\cdot\frac{1}{2}=3$

b)

Since we can't divide by zero, we need to find when:

$x^4-2x^2+144=0$

But before, we can factor the numerator and the denominator:

$\begin{gathered} \frac{3x^2(x^2+x-12)}{x^4-25x^2+144}=\frac{3x^2((x+4)(x-3))}{(x-3)(x-3)(x+4)(x+4)} \\ so: \\ \frac{3x^2}{(x+3)(x-4)} \end{gathered}$

Now, we can conclude that the vertical asymptotes are located at:

$\begin{gathered} (x+3)(x-4)=0 \\ so: \\ x=-3 \\ x=4 \end{gathered}$

so, for x = -3:

$\lim_{x\to-3^-}f(x)=\lim_{x\to-3^-}-\frac{162}{x^4-25x^2+144}=-162(-\infty)=\infty$ $\lim_{x\to-3^+}f(x)=\lim_{x\to-3^+}-\frac{162}{x^4-25x^2+144}=-162(\infty)=-\infty$

For x = 4:

$\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$ $\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$

4 0

9 months ago

You are allowed to eat at most 12 pieces of candy. You have already eaten 2. Write an inequality and solve to find how many more

I am Lyosha [343]

Answer:

One of the below.

Step-by-step explanation:

12-2=10 2+x=12

4 0

2 years ago