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san4es73 [151]
3 years ago
5

A sector with a radius of 6 cm has a central angle measure of 4pi/9 (in radians). What is the area of the sector?

Mathematics
1 answer:
Usimov [2.4K]3 years ago
8 0

Answer:

The area of the sector is 25.1327 cm²

Step-by-step explanation:

The area of a sector of circunference delimited by an angle in radians can be calculated by using the formula below:

area = (angle*r²)/2

area = [(4*pi/9)*(6)²]/2

area = [(4*pi/9)*36]/2

area = (144*pi/9)/2

area =  144*pi/18

area = 8*pi

area = 25.1327 cm²

The area of the sector is 25.1327 cm²

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Quadrilateral ABCD​ is inscribed in this circle.
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132°

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\implies \: x \degree + (3x - 12) \degree = 180 \degree \\  \\ \implies \: (4x - 12) \degree = 180 \degree \\  \\  \implies \: 4x - 12  = 180  \\  \\ \implies \: 4x   = 180  + 12 \\  \\ \implies \: 4x   = 192 \\  \\ \implies \: x   =  \frac{192}{4}  \\  \\ \implies \: x   = 48\\\\

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3 years ago
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Rufina [12.5K]

I'll focus on problem 19 and problem 22

============================================================

Problem 19

Answers:

  • x = 87
  • x+15 = 102

-------------------------------

Explanation:

The horizontal lines are parallel. Note the arrow markers along the interior portion of the lines. These similar markers tell us how the lines pair up to be parallel to one another.

Since the horizontal lines are parallel, this means the angles in question are congruent. They are corresponding angles.

x+15 = 102

x = 102-15

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Which leads to

x+15 = 87+15 = 102

============================================================

Problem 22

Answer: y = 27

-------------------------------

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3 years ago
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