Question

WILL MARK BRAINLIEST:

Answer 1

Answer:

y = -2x + 10

Step-by-step explanation:

In order to know this, first you need to know when two lines are perpendiculars. In this case, two lines are perpendiculars when the products of their pendings are equals to -1.

According to the above, if we have the 2nd equation which is y = x/2 + 3, we can know that the pending is 1/2 (The number next to the x will always be the pending of the line).

So, two lines would be perpendiculars when their products is -1 so:

1/2 * m = -1

solving for m:

1 * m = 2*(-1)

m = -2

With this, we know that the pending of the first line is -2 and we can assume that the first element of the equation of this line begins like this: y = -2x + b

However we need to know the y intercept or cut point of this line (i call it b here). We can also know this, because we have one point of this line, which is (1,8). These are the values of x and y respectively so, let's replace them in the equation above and solve for the cut point:

y = -2x + b

b = y + 2x

replacing 1 and 8 we have:

b = 8 + 2(1)

b = 10

Therefore, we can conclude that the equation of the line that passes through that point and is perpendicular to x/2 + 3 is:

y = -2x + 10

Answer 2

Answer:

The answer to your question is:         y = -2x + 10

Step-by-step explanation:

Data

Point = (1, 8)

Line    y = x/2 + 3

perpendicular

slope = 1/2  but the lines are perpendicular, then slope = -2

Equation

                    ( y - y1) = m ( x - x1)

                     (y - 8) = -2(x  - 1)

                     y - 8 = -2 x + 2

                     y = -2x + 2 + 8

                    y = -2x + 10