Answer:
45
Step-by-step explanation:
Answer:
See below
Step-by-step explanation:
Remember that quadratic functions are parabolas when graphed. The solutions are where the parabola crosses the x-axis.
1. The vertex of the parabola in f(x) is (0, 9) which is above the x-axis and the parabola opens up. So the parabola does not cross the x-axis. Therefore the solutions are imaginary.
2. The vertex of the parabola in g(x) is (9, 0) which is on the x-axis and parabola opens up. Therefore, there is a double solution.
3. The vertex of the parabola in h(x) is (-1, -9) which is below the x-axis and the parabola opens up. Therefore, there are two real solutions.
I know this is a long explanation, but that is a way of looking at the problem.
Answer:
Step-by-step explanation:
The x-intercepts exist where y is equal to 0...which is ON the x-axis. Hence, the name "x-intercept". These are caled zeros, solutions, and roots. This parabola goes through the x-axis at x = 0 and x = 4. It is at both of these locations where the y-coordinate is 0.
