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2 years ago

Subtract 0.58 - 0.21. What is the place value of the 7 in the difference? ones tens tenths hundredths

Mathematics

2 answers:

hoa [83]2 years ago

8 0

Answer:

hundredths place

Katyanochek1 [597]2 years ago

8 0

Answer:

Hundredth

Step-by-step explanation:

Given parameters are:

Two decimal numbers

1) 0.58

2) 0.21

Required?

1) Difference between the two numbers

2) Place value of 7

Calculating the difference

0 . 5 8

- 0 . 2 1

------------

0 . 3 7

The difference between the two decimal numbers is 0.37

In other words, 0.58 - 0.21 = 0.37

Calculating the place value of 7.

Place value are the value represented by a digit in a number on the basis of its position in the number.

To understand what place value is, we'll simplify the result of the subtraction.;

0.37 = 0.3 + 0.07

We'll then simplify individual numbers

0.3 = 3/10

0.07 = 7/100

The denominator of each fraction is their place value.

Below 7, we have 100.

Hence, it's place value is hundredth

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2 years ago

7. The probability that a randomly chosen student will be left-handed is .09: a) In a class of 108, find the probability that th

vampirchik [111]

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Required probability,

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$=P\left(\frac{7.5-9.72}{2.9741}< \frac{x-\mu}{\sigma}< \frac{8.5-9.72}{2.9741}\right)$

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$=P\left(\frac{11.5-9.72}{2.9741}< \frac{x-\mu}{\sigma}< \frac{12.5-9.72}{2.9741}\right)$

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2 years ago

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Dmitry [639]

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Solution:

Given expression is $\log _{6}(36)$ .

<u>To evaluate the expression:</u>

$\log _{6}(36)$

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$=\log _{6}\left(6^{2}\right)$

Using log rule: $\log _{a}\left(x^{b}\right)=b \cdot \log _{a}(x)$

$=2 \log _{6}(6)$

Using log rule: $\log _{a}(a)=1$ so that $\log _{6}(6)=1$

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2 years ago