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3 years ago

What is the measure of C?

Mathematics

2 answers:

Rufina [12.5K]3 years ago

8 0

Since the shape is a quadrilateral, the interior angles add to 360 degrees. Thus, angle C is 360 - 82 - 92 - 102 = 84 degrees.

ruslelena [56]3 years ago

3 0

84? Im not sure but i hope it helps

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In the stock market an amazon stock share rose 4 and 1/2 points on Wednesday rose 3 and 3/8 points on Thursday and fell 2 and 1/

Vika [28.1K]

Answer:

In the three days the Amazon stock share rose by $5\frac{5}{8}$

Step-by-step explanation:

Given:

Amazon stock share

rose 4 and 1/2 points on Wednesday

rose 3 and 3/8 points on Thursday

fell 2 and 1/4 points on Friday

To find the overall change.

Solution:

The change in share on Wednesday is given as = $+4\frac{1}{2}$

The change in share on Thursday is given as = $+3\frac{3}{8}$

The change in share on Friday is given as = $-2\frac{1}{4}$

Thus, the over all change is given by:

$4\frac{1}{2}+3\frac{3}{8}-2\frac{1}{4}$

In order to combine mixed numbers, we will work the whole numbers and the fractions separately.

⇒ $(4+3-2)+(\frac{1}{2}+\frac{3}{8}-\frac{1}{4})$

⇒ $5+(\frac{1}{2}+\frac{3}{8}-\frac{1}{4})$

To combine fractions, we will take least common denominator.

The L.C.D. 2,4 and 8 = 8 as it is the least common multiple for all the denominators

So, we multiply the numerators with the corresponding numbers to make the denominators common.

⇒ $5+(\frac{1\times 4}{2\times 4}+\frac{3}{8}-\frac{1\times 2}{4\times 2})$

⇒ $5+(\frac{4}{8}+\frac{3}{8}-\frac{2}{8})$

Combining the numerators.

⇒ $5+\frac{4+3-2}{8}$

⇒ $5+\frac{5}{8}$

⇒ $5\frac{5}{8}$

The overall change for the three days can be given as : $+5\frac{5}{8}$

This means the share rose by $5\frac{5}{8}$

5 0

3 years ago

100 points

inna [77]

$\huge{ \mathbf{ \underline{ Answer }\: \: ✓ }}$

The sand we need to fill the cylinders is equal to the total volume of the six cylindrical posts .

Given terms ( common for each cylinder ) :

height (h) = 4 ft
radius. (r) = 0.5 ft

$\large \boxed{ \mathrm{volume =\pi {r}^{2} h}}$

$3.14 \times \dfrac{1}{2} \times \dfrac{1}{2} \times 4$

$\mathrm{3.14 \: ft {}^{3} }$

Since volume of each cylinder is equal, so total volume of six cylindrical post :

$3.14 \times 6$

${ \mathrm{18.84 \: ft {}^{3} }}$

_____________________________

$\mathrm{ ☠ \: TeeNForeveR \:☠ }$

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