My advice is don't smoke and make sure you don't keep the two close together. Hope this helped,
Answer: ![\{y | \ y \in \mathbb{R}, \ y \ge 0\}](https://tex.z-dn.net/?f=%5C%7By%20%7C%20%5C%20y%20%5Cin%20%5Cmathbb%7BR%7D%2C%20%5C%20y%20%5Cge%200%5C%7D)
This translates to "y is any real number such that it is 0 or larger".
The reasoning is that the result of any absolute value function is either 0 or positive. In other words, we'll never get a negative result of an absolute value function. This is due to how absolute value represents distance. Negative distance does not make sense.
So if y = |x-3| then y = 0 is the smallest output possible. We could have any positive output we want.
In terms of a graph (see below), the V shape is at the lowest point (3,0). The y coordinate is all we care about in terms of finding the range. So we see the lowest y value is y = 0.
To minimize the cost, we take the straight distance from the refinery to the other side of the river as 2 km. Also, the 7 km will be the distance that has to be traveled by the pipeline in land. The total cost, C, is therefore,
total cost = (2 km)($800,000/km) + (7 km)($400,000 /km)
total cost = $4,400,000
Thus, the total cost of the pipeline is approximately $4,400,000.00.
3y - 3 = 2y + 6
-2y -2y
y - 3 = 6
-3 -3
y = 3