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NISA [10]
2 years ago
12

Learning Activities

Mathematics
2 answers:
igomit [66]2 years ago
8 0

Step-by-step explanation:

answers I the above photo

some of the questions are not clear

son4ous [18]2 years ago
7 0

Answer:

1. C(13inches)

2. A(40°)

3. B(126°)

4. C(50°)

5. 7cm

Step-by-step explanation:

According To the Question,

1. Given, The sum of all the sides of a STOP sign is 104 inches. A STOP sign is Octagon  with all sides equal.

Thus, Octagon has 8 equal side

So, Each Side Measure = 104/8 ⇔ 13inches

2. Given, In Triangle ABC, ∠A & ∠B each measure 70°

And, We Know Sum of all angles of a triangle is 180°.

Thus, ∠C = 180° - (∠A + ∠B)  ⇔  180°-140° ⇒ 40°

3. Given, The measures of the three angles of a quadrilateral are ∠A=49° ,∠B=58° & ∠C=127° .

And, We know sum of all angles of quadrilateral is 360°.

Thus, ∠D=360° - (∠A+∠B+∠C)  ⇔ 360°-234° ⇒ 126°

4. Given, The measure of all the Four angles of a quadrilateral are ∠A=(x+40)°, ∠B=130°, ∠C=x° & ∠D=(2x-10)° .

And, We know sum of all the angles of quadrilateral is 360°.

Thus, ∠A+∠B+∠C+∠D = 360°

Put all the Values, we get

x+40+130+x+2x-10 = 360

4x+160 = 360

4x = 200 ⇔ 200/4 ⇒ 50°

5. Given, the length of the two sides of an isosceles triangle are 3cm and 7cm .

Now, in order to form a triangle the sum of any two side of a triangle is always greater than the third side of a triangle.

So, We have an isosceles triangle in which two sides is always equal & we have given two sides of 3cm & 7cm .

Assume, if third side be 3cm (First Side+Third side > Second side)

3+3 ⇒6cm which is not greater than 7cm(thus, the Triangle not possible if we assume 3cm as triangle's third side)

Hence, The other Side of Triangle Surely be 7 cm.  

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Write a compound inequality that each graph could represent for the following questions.
ivanzaharov [21]

Answer:

Part 67) x > -2  and x < 3

Part 68) x\leq -1  or  x\geq 1

Step-by-step explanation:

Part 67) we know that

The solution of the number line is the interval -------> (-2,3)

All real numbers greater than -2 and less than 3

so

The compound inequality could be

x > -2  and x < 3

"And” indicates that, both statements must be true at the same time

Part 68) we know that

The solution of the number line is the interval (-∞,-1] ∪ [1,∞)

All real numbers less than or equal to -1 or all real numbers greater than or equal to 1    

The compound inequality could be

x\leq -1  or  x\geq 1

"Or” indicates that, as long as either statement is true, the entire compound sentence is true

3 0
2 years ago
Someone please help me with question 2
alukav5142 [94]

Answer:

v = s/t

v = (381.59 miles) / (5.5 hours)

v = 69.38 mph

8 0
3 years ago
Which of the following is an algebraic expression that represents the phrase X increased by 20
iren2701 [21]

Answer:

The expression means that X+20

5 0
2 years ago
Is the function even, odd or neither?<br> y=x^2-2x-8
mestny [16]

It is neither.

To be even, f(x) must equal f(-x).

If you substitute -x for x, you'd get

     y = (-x)^2 - 2(-x) -8

     y = x^2 +2x -8

This is not the same as the original, so this is not even.

To be odd, f(x) must equal -f(-x).

If you take the -x substitution from the last step and then multiply it by -1, you'd have:

      y = -1 (x^2 +2x -8)

      y = -x^2 -2x +8

This is not the same as the original either.

The function is neither even nor odd.

5 0
2 years ago
Read 2 more answers
Find an equation of the line passing through the pair of points. Write the equation in the form Ax +By = C.
Alexxandr [17]

9514 1404 393

Answer:

  5x -y = -37

Step-by-step explanation:

One way to find the coefficients A and B is to use the differences of the x- and y-coordinates:

  A = Δy = y2 -y1 = 2 -(-3) = 5

  B = -Δx = -(x2 -x1) = -(-7 -(-8)) = -1

Then the constant C can be found using either point.

  5x -y = 5(-7) -2 = -37

The equation of the line is ...

  5x -y = -37

_____

<em>Additional comment</em>

This approach comes from the fact that the slope of a line is the same everywhere.

  \dfrac{y-y_1}{x-x_1}=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{\Delta y}{\Delta x}\\\\\Delta x(y-y_1)=\Delta y(x-x_1)\qquad\text{cross multiply}\\\\\Delta y(x-x_1)-\Delta x(y-y_1)=0\qquad\text{subtract y term}\\\\\Delta y(x) -\Delta x(y) = \Delta y(x_1)-\Delta x(y_1)\qquad\text{Ax+By=C form}

The "standard form" requires that A be positive, so we chose point 1 and point 2 to make sure that was the case.

5 0
2 years ago
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