This question is a simple answer just combine the like terms.
Your final answer is: 3x+2y+2
For this problem, let's assign variables for the unknown parameters. Let x be the value for student tickets, while y be the value for chaperone tickets. The two equations formulated would be:
59x + 6y = 508 --> eqn 1
x = 2+y --> eqn 2
Rearranging eqn 2,
y = x - 2
Substituting this to eqn 1 and solving for x,
59x + 6(x - 2) = 508
59x + 6x - 12 = 508
x = 8
Thus, each student ticket costs $8.
