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nika2105 [10]
3 years ago
10

Write the first six cube if natural number​

Mathematics
2 answers:
valkas [14]3 years ago
8 0

Answer:

The cube of first six natural numbers are

1, 8, 27, 65, 125, 216

Step-by-step explanation:

Natural Numbers are known as 1, 2, 3, 4, ..., ∞

Now,

For Cube of first six natural numbers

1³ = 1

2³ = 8

3³ = 27

4³ = 64

5³ = 125

6³ = 216

Thus, The cube of first six natural numbers are

1, 8, 27, 65, 125, 216

<u>-TheUnknownScientist</u>

valkas [14]3 years ago
6 0

Answer:

1³ = 1

2³ = 8

3³ = 27

4³ = 64

5³ = 125

6³ = 216

Step-by-step explanation:

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Use the recursive formula f(n) = 0.4 . f(n-1) + 12 to determine the 2nd term if f(1) = 4.
Irina18 [472]

Answer:

Assuming you have f(n)=0.4f(n-1)+12 with f(1)=4, the answer is f(2)=13.6.

Step-by-step explanation:

I think that says f(n)=0.4f(n-1)+12 with f(1)=4.

Now we want to find f(2) so replace n with 2:

This gives you:

f(2)=0.4f(2-1)+12

f(2)=0.4f(1)+12

f(2)=0.4(4)+12

f(2)=1.6+12

f(2)=13.6

5 0
3 years ago
Read 2 more answers
If you could help that would be nice!
Arturiano [62]
6 + 4 + 4 = 14 cm
2 * pi * r = 
2 * 3.14 * 3 = 18.84 / 2 = 9.42
14 + 9.42 = 23.42
5 0
3 years ago
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An airline finds that 5% of the persons making reservations on a certain flight will not show up for the flight. If the airline
vivado [14]

Answer:

The answer to the question is;

The probability that a seat will be available for every person holding a reservation and planning to fly is 0.63307.

Step-by-step explanation:

Let the sample size =n = 100

The success probability = 5 % = 0.05

Number of tickets sold = 105 tickets

In the case where there the airline has found that 5 % will not show up, then every passenger should have  a seat, we have  

A Binomial distribution is appropriate where there is a chance for a certain number of successful outcomes from a number of independent trails

However n·p and n·q must be ≥ 5 for there to be a normal approximation of a Binomial distribution thus

n·p = 105×0.05 =  5.25 ≥ 5

and n·q = n(1 - p) = 105 (1 - 0.05) = 99.75 ≥ 5

As the requirements are met, we can proceed with the approximation of the Binomial distribution by the normal distribution

 z = \frac{x-np}{\sqrt{np(1-p)}  } = \frac{4.5 - 105*0.05}{\sqrt{105*0.05(1-0.05)} } =  - 0.3358

We therefore have P(x ≥ 5) = P( x > 4.5) = P(z > -0.34) = 1 - P(z < -0.34) = 1 -0.36693 = 0.63307

Another way to solve the question is as follows

p = 0.95 q = 0.05

μ = np = 0.95*105 = 99.75, σ = \sqrt{npq} = 2.233

P (x≤100) = P(z = P(z<0.34) = 0.63307.

6 0
3 years ago
Please thanks please please thanks
monitta

Answer:

72 hope this helps you!?!?!!?

7 0
3 years ago
If Mr. O'Brien cuts five lawns per day at $40 each, and he has a goal of making $3500, how many days will it take to reach that
Ede4ka [16]

Answer:

17 days and a half.

Step-by-step explanation:

First, we can find how much money he makes per day cutting lawns. This can be found with the equation:

40 x 5 = 200

He makes $200 a day cutting lawns.

Now we can divide his goal money ($3500) by his daily rate ($200) to get the number of days it will take to reach his goal.

3500 ÷ 200 = 17.5

It will take him 17.5 days to reach his goal.

5 0
3 years ago
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