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nika2105 [10]
3 years ago
10

Write the first six cube if natural number​

Mathematics
2 answers:
valkas [14]3 years ago
8 0

Answer:

The cube of first six natural numbers are

1, 8, 27, 65, 125, 216

Step-by-step explanation:

Natural Numbers are known as 1, 2, 3, 4, ..., ∞

Now,

For Cube of first six natural numbers

1³ = 1

2³ = 8

3³ = 27

4³ = 64

5³ = 125

6³ = 216

Thus, The cube of first six natural numbers are

1, 8, 27, 65, 125, 216

<u>-TheUnknownScientist</u>

valkas [14]3 years ago
6 0

Answer:

1³ = 1

2³ = 8

3³ = 27

4³ = 64

5³ = 125

6³ = 216

Step-by-step explanation:

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This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex
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Answer:

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There are multiple ways of using lagrange multipliers. Most of them are equivalent.

Consider the function F(x,y) = x^2-y^2-\lambda(x^2+y^2-64). We want the following \frac{\partial F}{\partial x} = \frac{\partial F}{\partial y} = \frac{\partial F}{\partial \lambda} = 0.

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