3 years ago

The length of a rectangle is 6 meters more than its width. If the area is 135 square meters, what is its width?

Mathematics

1 answer:

Novay_Z [31]3 years ago

4 0

Length = width +6

L * (L - 6) = 135

L^2 - 6L = 135

L^2 - 6L -135 = 0

Length = 15
Width = 9

You might be interested in

What is (3xy^2)(-6xy^4)

krok68 [10]

Answer:

$-18x^2y^6$

Step-by-step explanation:

we have

$(3xy^2)(-6xy^4)$

Applying property of exponents

$x^{m} x^{n}=x^{m+n}$

$(3xy^2)(-6xy^4)=(3)(-6)(x^{1+1})(y^{2+4})=(-18)(x^{2})(y^{6})=-18x^2y^6$

5 0

3 years ago

Someone get me the answers ASAP!! thank you

elena-s [515]

It's 11 because 6+5=11 other words it means it's 11 squares away

3 0

3 years ago

The length of a swimming pool is 4 feet longer than 2 times its width. If the perimeter of the pool is 128 feet, what is the wid

alexandr1967 [171]

P = 2(L + W)
P = 128
L = 2W + 4

128 = 2(2W + 4 + W)
128 = 2(3W + 4)
128 = 6W + 8
128 - 8 = 6W
120 = 6W
120/6 = W
20 = W <=== width is 20 ft

L = 2W + 4
L = 2(20) + 4
L = 40 + 4
L = 44 <=== length is 44 ft

5 0

3 years ago

WHAT IS 24 DIVIDED BY 48 WITH WORK PLEASE

kotegsom [21]

So,

$\frac{24}{48}$

Write in prime factored form.
$\frac{2*2*2*3}{2*2*2*2*3}$

Cross-cancel
$\frac{1}{2}$

7 0

3 years ago

Read 2 more answers

If the instructions for a problem ask you to use the smallest possible domain to completely graph two periods of y = 5 + 3 cos 2

Finger [1]

The period of a sinusoid $\cos 2(x-c)$ is $\dfrac{2\pi}2=\pi$ , so any range such that $\mathrm{Xmax}-\mathrm{Xmin}=2\pi$ will give two complete periods.

5 0

3 years ago

Read 2 more answers