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3 years ago

Simplify.

Mathematics

1 answer:

erma4kov [3.2K]3 years ago

7 0

(5b^2 - 3b + 2) + (2b - 4)
Just expand out all the brackets
5b^2 - b - 2

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Which ratio is equivlant to 3:4

Crank

Answer:

There is multiple. You didnt give options so heres all of them.

Step-by-step explanation:

6 : 8 9 : 12 12 : 16 15 : 20 18 : 24 21 : 28 24 : 32 27 : 36 30 : 40 33 : 44 36 : 48 39 : 52 42 : 56 45 : 60 48 : 64 51 : 68 54 : 72 57 : 76 60 : 80 63 : 84 66 : 88 69 : 92 72 : 96 75 : 1007 8 : 104 81 : 108 84 : 112 87 : 116 90 : 120 93 : 124 96 : 128 99 : 132 102 : 136 105 : 140 108 : 144 111 : 148 114 : 152 117 : 156 120 : 160 123 : 164 126 : 168 129 : 172 132 : 1761 35 : 180 138 : 184 141 : 188 144 : 192 147 : 196 150 : 200 153 : 204 156 : 208 159 : 2121 62 : 216 165 : 220 168 : 224 171 : 228 174 : 232 177 : 236 180 : 240 183 : 244 186 : 248 189 : 252 192 : 256 195 : 260 198 : 264 201 : 268 204 : 272 207 : 276 210 : 280 213 : 284 216 : 288 219 : 292 222 : 296 225 : 300 228 : 304 231 : 308 234 : 312 237 : 316 240 : 320 243 : 324246 : 328249 : 332252 : 336255 : 340258 : 344261 : 348264 : 352267 : 356270 : 360273 : 364276 : 368279 : 372282 : 376285 : 380288 : 384291 : 388

etc etc

4 0

3 years ago

30 POINTS! PLEASE HELP!

Sauron [17]

Step-by-step explanation:

(7x^4-4y^8)^2

5 0

4 years ago

Write an equation of the line passing through the points (4.15) and (-1. - 15).

jolli1 [7]

Answer:

y = 6x - 9

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Slope Formula: $m=\frac{y_2-y_1}{x_2-x_1}$

Slope-Intercept Form: y = mx + b

m - slope

b - y-intercept

Step-by-step explanation:

Step 1: Define

Point (4, 15)

Point (-1, -15)

Step 2: Find slope m

Substitute: $m=\frac{-15-15}{-1-4}$
Subtract: $m=\frac{-30}{-5}$
Divide: $m=6$

Step 3: Find y-intercept b

Define: y = 6x + b
Substitute: -15 = 6(-1) + b
Multiply: -15 = -6 + b
Isolate b: -9 = b
Rewrite: b = -9

Step 4: Write linear equation

Substitute in all variables.

y = 6x - 9

And we have our answer!

4 0

3 years ago

Question 1: The diagonal of a rectangle, with base x, remains at a fixed

kramer

We have that The height changing rate when the length of the base is 2 cm

$dh/dt=-7.2cm/s$

From the question we are told

The diagonal of a rectangle, with base x, remains at a fixed value of 3cm. If the base is increasing at a rate of 8 cm/s. at what rate is the height changing when the length of the base is 2 cm?

Generally the Pythagoras equation for the triangle is mathematically given

$r^2=h^2+x^2$