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GREYUIT [131]
3 years ago
9

Suppose the roots of the equation 2x^2−5x−6=0 are α and β.Find the quadratic equation with roots 1/α and 1/β.​

Mathematics
1 answer:
pochemuha3 years ago
8 0

Answer:

6x² + 5x - 2 = 0

Step-by-step explanation:

Given

2x² - 5x - 6 = 0 ← in standard form

with a = 2, b = - 5, c = - 6, then

sum of roots α + β = - \frac{b}{a} = \frac{5}{2}

product of roots = \frac{c}{a} = - 3, then

sum of new roots = \frac{1}{\alpha } + \frac{1}{\beta }

= \frac{\beta+\alpha  }{\alpha \beta }

= \frac{\frac{5}{2} }{-3} = - \frac{5}{6}

product of new roots = \frac{1}{\alpha } × \frac{1}{\beta }

= \frac{1}{\alpha\beta  } = - \frac{1}{3}

Hence the required equation is

x² + \frac{5}{6} x - \frac{1}{3} = 0 or

6x² + 5x - 2 = 0 ( multiplying through by 6 )

                           

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