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3 years ago

One of the factors of the polynomial x3 + 5x2 + 6x is (x2 + 3x). What is the other factor?

Mathematics

2 answers:

oksano4ka [1.4K]3 years ago

7 0

The given polynomial is :

$x^{3}+5x^{2}+6x$

One factor is given as : $x^{2} +3x$ or $x(x+3)$

So, now solving this for 2nd factor, we get,

$x(x^{2}+5x+6 )$

$x[(x^{2}+3x+2x+6)]$

$x(x+3)(x+2)$

Hence, the second factor is (x+2)

labwork [276]3 years ago

6 0

The answer is

x (x² + 5x + 6) 
-------------------- 
x ( x + 3) 

( x + 3 ) (x + 2) 
--------------------- 
x + 3 

x + 2

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The percent increase is 6% because it increased by 6 and 6 is 6% of 100.
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3 years ago

Question 1 (1 point)

olga55 [171]

Answer:

1) $2y^{2}+4y-9$

2) $18x^{5}y^{4}z$

3) $6x^{5}-12x^{4}+9x^{3}$

4) 40

5) $x^{3}-7x^{2}+3x+36$

Step-by-step explanation:

1) Distribute the negative sign that is outside the parentheses and then you must add like terms, as following:

$(y^{2}-3y-5)-(-y^{2}-7y+4)=y^{2}-3y-5+y^{2}+7y-4=2y^{2}+4y-9$

2) According to the Product property of exponents, when you multiply powers with the same base, you must add the exponents. Then:

$(6xy^{3}z)(3x^{2}yx^{2})=18x^{5}y^{4}z$

3) Apply the Distributive property and the Product property of exponents. Then, you obtain:

$-3x^{3}(-2x^{2}+4x-3)=6x^{5}-12x^{4}+9x^{3}$

4) $(4a+5)^{2}$ is a square of a sum, then, by definition you have:

$(a+b)^{2}=a^{2}+2ab+b^{2}$

Then:

$(4a+5)^{2}=(4a)^{2}+2(4a)(5)+5^{2}=16a^{2}+40a+25$

The coefficient of the second term is the number in front of the variable a. Then, the answer is: 40

5) Apply the Distributive property and the Product property of exponents, then, oyou must add the like terms:

$(x-4)(x^{2}-3x-9)=x^{3}-3x^{2}-9x-4x^{2}+12x+36=x^{3}-7x^{2}+3x+36$

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3 years ago

Tara is the editor of the school newspaper. She tries to devote about 1/2 of the paper to news, 1/3 to pictures, and the remaind

Klio2033 [76]

5/6 of the paper is devoted to news and pictures

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1/3
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3×2=6
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now you would be able to add the numerators, so 2+3=5
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3 years ago