V =


h
1. Find the radius.
8/2 = 4
2. Square the radius.

= 16
3. Multiply that by pi.
3.14 * 16 = 50.24
4. Multiply that by the height.
50.24 * 20 = 1004.8
5. Now find 60% of that.
1004.8 * 0.6 = 602.88
V = 602.88

Honestly, it's been a while since I've done this, but I believe this is the answer.
Answer:
495 combinations of 4 students can be selected.
Step-by-step explanation:
The order of the students in the sample is not important. So we use the combinations formula to solve this question.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.

How many combination of random samples of 4 students can be selected?
4 from a set of 12. So

495 combinations of 4 students can be selected.
Step 1
Find the area of one equilateral triangle
Applying the law of sines

in this problem
a=b=7 cm
C=60 degrees
so

cm²
Step 2
To calculate the area of the hexagon multiply the area of one equilateral triangle by 
cm²
therefore
the answer is the option
73.5 sqrt 3cm²
Associative property
(3 + 9) + 6 = 3 + (9 + 6)
The difference would be subtracting the variables and the dividing the difference by 2