Which Postulate/Theorem below would prove that the triangles shown below are congruent?

Mathematics

1 answer:

velikii [3]3 years ago

3 0

Answer:

Correct answer is D. ASA

Step-by-step explanation:

Let us first define ASA congruence rule:

2 triangles are called congruent according to ASA congruence rule if 2 angles of the triangle and the corresponding side between these two angles are equal to each other.

In the question figure, we can figure out following conclusions from Triangles $\triangle SRT\text{ and }\triangle WXY$ respectively:

$\angle TRS = \angle YXW$
Side RS = Side WX
$\angle TSR = \angle YWX$

As per the definition of option d) ASA congruence, the triangles are congruent.

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A student is asked to find the length of the hypotenuse of a right triangle. The length of one leg is 32

zavuch27 [327]

$Hypotenuse =39cm$ of right angle triangle! .

Step-by-step explanation:

Here we have , A student is asked to find the length of the hypotenuse of a right triangle. The length of one leg is 32 centimeters, and the length of the other leg is 25 centimeters. The student incorrectly says that the length of the hypotenuse is 7.5 centimeters. We need to find:

We have , One length as 32 cm and other as 25 cm , as

$Perpendicular = 32cm\\Base=25cm$

By Pythagoras Theorem ,

⇒ $Hypotenuse^2 = Perpendicular^2+Base^2$

⇒ $Hypotenuse^2 =32^2+22^2$

⇒ $\sqrt{Hypotenuse^2} =\sqrt{1024+484}$

⇒ $Hypotenuse =39cm$

So , $Hypotenuse =39cm$ of right angle triangle! .

4 0

3 years ago

Read 2 more answers

Create a matrix for this system of linear equations, The determinant of the coefficient matrix is

marin [14]

Answer: The determinant of the coefficient matrix is -15 and x = 3, y = 4, z = 1.

Step-by-step explanation: The given system of linear equations is :

$2x+y+3z=13~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\x+2y=11~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)\\\\3x+z=10~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)$

We are given to find the determinant of the coefficient matrix and to find the values of x, y and z.

The determinant of the co-efficient matrix is given by

$D=\begin{vmatrix}2 & 1 & 3\\ 1 & 2 & 0\\ 3 & 0 & 1\end{vmatrix}=2(2-0)+1(0-1)+3(0-6)=4-1-18=-15.$

Now, from equations (ii) and (iii), we have

$x+2y=11~~~~~\Rightarrow y=\dfrac{11-x}{2}~~~~~~~~~~~~~~~~~~~~~~~~~~(iv)\\\\\\3x+z=10~~~~~~\Rightarrow z=10-3x~~~~~~~~~~~~~~~~~~~~~~~~~(v)$

Substituting the value of y and z from equations (iv) and (v) in equation (i), we get

$2x+y+3z=13\\\\\Rightarrow 2x+\dfrac{11-x}{2}+3(10-3x)=13\\\\\Rightarrow 4x+11-x+60-18x=26\\\\\Rightarrow -15x+71=26\\\\\Rightarrow -15x=26-71\\\\\Rightarrow -15x=-45\\\\\Rightarrow x=3.$