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Neporo4naja [7]
10 months ago
12

What are the factors to the equation 4x2-52x + 169 121? A 4(x-1)(x+12) B 4(x + 1)(x - 12) C. 4(x + 1)(x+12) D. 4(x-1)(x - 12)

Mathematics
1 answer:
Bingel [31]10 months ago
5 0

The given equation is,

4x^2-52x+169=121

Simplifying the above equation,

\begin{gathered} 4x^2-52x+169-121=0 \\ 4x^2-52x+48=0 \end{gathered}\begin{gathered} 4x^2-13\times4x+4\times12=0 \\ 4(x^2-13x+12)=0 \\ 4(x^2-12x-1x+12\times1)=0 \\ 4(x(x-12)-1(x-12))=0 \\ 4(x-12)(x-1)=0 \end{gathered}

Therefore, the factors of the given expression is 4(x-1)(x-12).

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8 0
3 years ago
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Fill in the missing numbers along the sides of the triangle so that it contains each of the numbers from 4 through 12 exactly on
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Answer:  A B == 9 + 11   CD == 5 +7  E F == 6 + 10

Step-by-step explanation:

(This reminds me of a "formula" I developed a few years ago when I was photographing formal groups, and had to figyre out how many people to put in each row, and the rows had to be different lengths)  Anyway--

Get the sum of the numbers at the angles, subtract that number from 32, and that's the amount needed for the row.

Once I have that number, divide by 2 and split as "n + 1 and n-1

AB side:  angles given: 8 +4=12 , 32-12 =20  20/2 = 10;  10+1 =11  10-1=9

CD side: angles given:  8 + 12 =20, 32-20=12; 12/2 =6  6+1 =7 6-1 =5

EF side: angles given:  4 + 12 =16 32-16=16  My formula would have yielded 7+9, but those numbers were already used. Conveniently, 10 + 6 are left over.   Same principle, but + or - 2.

Thanks for the opportunity to work in this!

It is a fun way for me to end my participation in Brainly for a while. My school year is over!

Good Luck, Stay Safe!

8 0
3 years ago
Point A(3,2) is on a circle whose center is C(−2,3). What is the radius of the circle?
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Answer:

The radius of the circle is √26.

Step-by-step explanation:

Since point A is on the circle, the distance between that point and the center of the circle is equal to the radius.

To find the distance between two points, the following equation should be used:

x^{2} =(x_{A}- x_{C}) ^{2} + (y_{A}- y_{C}) ^{2}

Replacing the numeric values:

r^{2} =(3- (-2)) ^{2} + (2-3) ^{2}\\r^{2} =(5) ^{2} + (-1) ^{2}\\r=\sqrt{26}

The radius of the circle is √26.

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3 years ago
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6 0
3 years ago
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