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Alexxandr [17]
3 years ago
9

Do you go to the movies at least twice a week?

Mathematics
1 answer:
egoroff_w [7]3 years ago
5 0

Answer:

We are given the below table of information:

                       Yes                No                  Total

Male                 35                  45                   80

Female             67                  28                   95

Total                  102                73                   175


We have to find the probability that a person who does not go to the movies at least twice a week is female.

We know that there are 73 students who does not go to the movies at least twice a week

Also we know that there are 28 female's who does not go to the movies at least twice a week.

Therefore, the probability that a person who does not go to the movies at least twice a week is female is:

\bold{\frac{28}{73}=0.384}





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3 years ago
Which term of ap 30,27,24is0
son4ous [18]

Answer:

11th term is 0

Step-by-step explanation:

30, 27 , 24 ,......0

a = first term = 30

Common difference = second term - first term = 27 - 30 = -3

nth term = a+(n-1)*d

a + (n-1)d = 0

30 + (n - 1) *(-3) = 0

30 + n*(-3) -1*(-3) = 0

30 - 3n + 3 = 0

      -3n + 33 = 0

               -3n = -33

                   n = -33/-3

n = 11

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3 years ago
A parllogram has a hight of 3.5 and the weith is 3.1 what is the area
scZoUnD [109]
Area of parallelogram = width x height
Area of parallelogram = 3.1 x 3.5
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4 years ago
Help me pls due 9-24-18
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Prove by mathematical induction that 1+2+3+...+n= n(n+1)/2 please can someone help me with this ASAP. Thanks​
Iteru [2.4K]

Let

P(n):\ 1+2+\ldots+n = \dfrac{n(n+1)}{2}

In order to prove this by induction, we first need to prove the base case, i.e. prove that P(1) is true:

P(1):\ 1 = \dfrac{1\cdot 2}{2}=1

So, the base case is ok. Now, we need to assume P(n) and prove P(n+1).

P(n+1) states that

P(n+1):\ 1+2+\ldots+n+(n+1) = \dfrac{(n+1)(n+2)}{2}=\dfrac{n^2+3n+2}{2}

Since we're assuming P(n), we can substitute the sum of the first n terms with their expression:

\underbrace{1+2+\ldots+n}_{P(n)}+n+1 = \dfrac{n(n+1)}{2}+n+1=\dfrac{n(n+1)+2n+2}{2}=\dfrac{n^2+3n+2}{2}

Which terminates the proof, since we showed that

P(n+1):\ 1+2+\ldots+n+(n+1) =\dfrac{n^2+3n+2}{2}

as required

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3 years ago
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