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Mademuasel [1]
2 years ago
12

What is the probability that you roll at least one 3 in your dice? Convert your answer to

Mathematics
1 answer:
ivann1987 [24]2 years ago
5 0

Answer:

0.167

Step-by-step explanation:

1 dice has 6 faces, 2 dice will have a total of 12 faces

1 dice has 1 face with a 3 on it, so 2 dices will have 2 total 3s on them.

2 /12 = 1/6 = 0.16666666666

Rounded to 3 d.p = 0.16666

= 0.167

Answered by Gauthmath

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0.5x + 6 &gt; 3<br> I don’t know how to solve
Advocard [28]

Answer:

x > -6

Step-by-step explanation:

Move 6 to the other side:

0.5x > -3

x > -6

3 0
3 years ago
I don't understand this question. Could anyone excplain to me what it wants me to do and what the answer is?
Hatshy [7]
The answer is 18.2
I got the answer by solving it
7 0
3 years ago
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What is 0.019 written as a percent?<br><br> A. 0.00019% <br> B. 0.019%<br> C. 0.19% <br> D. 1.9%
Lesechka [4]
The correct option is d
7 0
3 years ago
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2(w – 3y + 4) + w – 5
melisa1 [442]

Answer: It should be 3w - 6y + 3

Step-by-step explanation:

-Solve:

2(w-3y+4)+w-5

-Use Distributive Property:

2(w-3y+4)+w-5

2w-6y+8+w-5

-Then, combine like terms:

2w-6y+8+w-5

3w-6y+3

Result:

3w-6y+3

3 0
3 years ago
If y-3x=9, 7x+y=25, what is the value of x and y?
lianna [129]

\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?

\bold{\rm{Solution}} \text{: We'll solve this by substitution method}

\dashrightarrow  y - 3x = 9 \\  \\  \dashrightarrow   \boxed{y = 9 + 3x } \qquad .. \sf eq(1)

\text{we got the value of y now getting the value of x}

\looparrowright 7x + y = 25 \\  \\  \looparrowright 7x = 25 - y \\  \\  \looparrowright  \boxed{x =   \frac{25 - y}{7}} \qquad .. \sf eq(2)

\text{Now, putting y = 9 + 3x in eq(2)}

\hookrightarrow  x =  \frac{25 - y}{7}   \\  \\ \hookrightarrow  x =  \frac{25 - 9 + 3x}{7}  \\  \\ \hookrightarrow  7x =  25 - 9 + 3x \\  \\ \hookrightarrow  7x - 3x =  16 \\  \\ \hookrightarrow  4x = 16 \\  \\ \hookrightarrow  x =  \frac{16}{4}  \\  \\ \star \quad  \boxed{ \green{ \frak{ x = 4}}}

\text{Now we know the value of x, for getting y we need to put x in eq(1)}

: \implies y = 9 + 3x \\  \\   : \implies y = 9 + 3(4) \\  \\  : \implies y = 9 + 12  \\  \\    \star \quad  \boxed{\frak{  \green{y = 21}}}

\text{Hence, values of x and y are} \:  \frak{ \green{4}}  \: \text{and} \:  \frak{ \green{21}} \: \text{respectively}.

4 0
2 years ago
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