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rodikova [14]
4 years ago
10

Four parallel lines are drawn in a rectangular sign. The sign is painted using two colors in an alternating pattern, as shown.

Mathematics
2 answers:
kolezko [41]4 years ago
6 0

Look at the shaded areas and then read A. A rectangle has 2 sets of parallel lines (as these two figures do) and 1 right angle somewhere.  These two shaded regions do not have 1 right angle.

B: B is not correct because the shaded figures have 2 sets of 2 equal lines. A rhombus has 4 equal lines.

C: Not true either. The lines have 2 sets of parallel lines. Trapezoids have only 1 set.

D.  D is true

E.  E is true.


Perhaps you are not supposed to consider what the figures look like. I don't know how to answer the question. You likely got the same answers I did. Any chance you copied the wrong diagram?

Digiron [165]4 years ago
6 0

Answer:

D and E

Step-by-step explanation:

--A: A rectangle has 2 sets of parallel lines (as these two figures do) and 1 right angle somewhere.  These two shaded regions do not have 1 right angle.

--B: B is not correct because the shaded figures have 2 sets of 2 equal lines, a rhombus has 4 equal lines.

--C: Not true either. The lines have 2 sets of parallel lines. Trapezoids have only 1 set.

<u>D.  D is true</u>

<u>E.  E is true.</u>

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Alan travels eight and two thirds kilometers to get to school. He ran one and ten elevenths kilometers and walked the rest. How
kow [346]

Answer:

6 2/3 or 6 20/30

Step-by-step explanation:

8 2/3 = 8 22/33

1 10/11 = 1 30/33

8 22/33 = 7 52/33

7 52/33 - 1 30/33 = 6 20/30 = 6 2/3

(33 is the common denominator)

hope this helped (:

7 0
3 years ago
Read 2 more answers
What's the intuition behind the equation 1+2+3+⋯=−1121+2+3+⋯=−112 ?
Aleks [24]
The sum clearly diverges. This is indisputable. The point of the claim above, that

1+2+3+\cdots=-\dfrac1{12}

is to demonstrate that a sum of infinitely many terms can be manipulated in a variety of ways to end up with a contradictory result. It's an artifact of trying to do computations with an infinite number of terms.

The mathematician Srinivasa Ramanujan famously demonstrated the above as follows: Suppose the series converges to some constant, call it C. Then

\begin{matrix}C&=&1&+2&+3&+4&+5&+6&+\cdots\\4C&=&&+4&&+8&&+12&+\cdots\\-3C&=&1&-2&+3&-4&+5&-6&+\cdots\end{matrix}

Now, recall the geometric power series

\displaystyle\sum_{n\ge0}x^n=1+x+x^2+x^3+\cdots=\dfrac1{1-x}

which holds for any |x|. It has derivative

\displaystyle\sum_{n\ge1}nx^{n-1}=1+2x+3x^2+4x^3+\cdots=\dfrac1{(1-x)^2}

Taking x=-1, we end up with

1+2(-1)+3(-1)^2+4(-1)^3+\cdots=1-2+3-4+\cdots=\dfrac14

and so

-3C=\dfrac14\implies C=-\dfrac1{12}

But as mentioned above, neither power series converges unless |x|. What Ramanujan did was to consider the sum 1-2+3-4+\cdots as a limit of the power series evaluated at x=-1:

\displaystyle-3C=\lim_{x\to-1^+}\sum_{n\ge1}nx^{n-1}=\lim_{x\to-1^+}\frac1{(1-x)^2}=\frac14

then arrived at the conclusion that C=-\dfrac1{12}.

But again, let's emphasize that this result is patently wrong, and only serves to demonstrate that one can't manipulate a sum of infinitely many terms like one would a sum of a finite number of terms.
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STatiana [176]
I got C.75 liters.

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6 0
4 years ago
If the diameter of a circle is 22, what is the circumference?
andreev551 [17]

Answer:

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Formula for a circle

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