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LiRa [457]
1 year ago
8

SOCIAL SECURITY Social Security numbers are of the form XYZ - MN - ABCD. A. The first three digits XYZ are referred to as the ar

ea number. The number is associated with where you registered for your social security card. X is a number 1-7. Y and Z can be any number 0-9. Also the area code 666 has never been used. How many area code numbers are possible? 10SHOW YOUR WORK
Mathematics
1 answer:
aev [14]1 year ago
6 0

Social Security numbers are of the form XYZ - MN - ABCD

Part A:

The first three digits XYZ are referred to as the area number

X is a number 1 - 7 (1, 2, 3, 4, 5, 6, 7)

That means we have 7 choices for X

Y and Z can be any number 0 - 9 (0, 1, 2, 3, 4, 5, 6, 7, 8, 9)

That means we have 10 choices for Y and also 10 choices for Z

So, the number of possible ways are

7\times10\times10=700

But we know that the area code 666 has never been used.

So we need to subtract this one from the total.

700-1=699

Therefore, the total number of possible area codes is 699.

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Answer:

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Step-by-step explanation:

It is given that the Nickel Charge Proportions found  in the battery are:

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a) P(cell has at least one of the positive nickel-charged options) = P(a cell has +2 nickel-charged options) + P(a cell has +3 nickel-charged options) + P(a cell has +4 nickel-charged options) = 0.35 + 0.33 + 0.15 = 0.83.

Or:

P(a cell has at least one of the positive nickel-charged options) = 1 - P(a cell has 0 nickel-charged options) = 1 - 0.17 = 0.83.

b) P(a cell is not composed of a positive nickel charge greater than +3) = 1 - P(a cell is composed of a positive nickel charge greater than +3)

= 1 -  P(a cell has +4 nickel-charged options)  '.' because +4 is only positive nickel charge greater than +3      

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To summarize:

P(cell has at least one of the positive nickel-charged options) = 0.83!!!

P(a cell is not composed of a positive nickel charge greater than +3) = 0.85!!!

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