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3 years ago

14

Michael took in 91 mile bike trip. he left home at 7 AM. If he stopped for a total of two hours for rest and food and averaged 1

4 mph, what time did he arrive at his destination?

1 answer:

Korvikt [17]3 years ago

5 0

Distance = rate * time
t = d / r

t = 91 / 14 = 6.5 hrs

plus 2 hour rest stop

8.5 hrs

start at 7 AM
end at 3:30 PM

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Answer:

See Explanation

Step-by-step explanation:

Solving (a):

First, we categorize each data (to get their frequencies):

PI PI PI PI PI PI PI PI PI ---> Frequency: 9

S S S S S S S S---> Frequency: 8

V V V V V V V V V V V V V ---> Frequency: 13

PO PO PO---> Frequency: 3

B ---> Frequency: 1

C C ---> Frequency: 2

Total = 36.

The frequency table is as follows:

$\begin{array}{cc}{Pizza\ Topping} & {Frequency} & {Beacon\ or\ Ham} & {9} & {Seafood} & {8} \ \\ {Vegetable\ and Fruit} & {13} & {Poultry} & {3} & {Beef} & {1} & {Cheese} & {2}\ \end{array}$

Solving (b): The relative frequency and percentage.

Relative frequency is calculated by dividing each frequency by the total frequency.

So, we have:

${Beacon\ or\ Ham} = \frac{9}{36} =0.250$

$Seafood = \frac{8}{36} =0.222$

$Fruits\ and\ Vegetable = \frac{13}{36}=0.361$

$Poultry = \frac{3}{36}=0.083$

$Beef = \frac{1}{36}=0.028$

$Cheese = \frac{2}{36}=0.056$

The percentage is calculated by multiplying the frequency by 100%.

So, we have:

$Bacon\ or\ Ham = 0.250 * 100\% = 25.0\%$

$Seafood = 0.222 * 100\% = 22.2\%$

$Fruits\ and\ Vegetable= 0.361 * 100\% = 36.1\%$

$Poultry = 0.083 * 100\% = 8.3\%$

$Beef = 0.028 * 100\% = 2.8\%$

$Cheese = 0.056 * 100\% = 5.6\%$

Solving (c): Percentage that mentioned vegetables and fruits, poultry, or cheese?.

This is calculated as:

$\%Percent = Vegetable\ and\ fruits + Poultry + Cheese$

$\%Percent = 36.1\% + 8.3\% + 5.6\%$

$\%Percent = 50\%$

(d) See attachment for bar graph

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Answer:

3men = 4houses= 5days

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Answer:

Let us assume cost of each pineapple cake = $x.

Cost of each chocolate cakes = $y.

On weekdays 45 pineapple cakes and 62 chocolate cakes were sold.

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Therefore, first equation would be

45x + 62y = 3520 --------------equation(1).

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Therefore, second equation would be

55x + 79y = 4415 --------------equation(2).

Therefore, system of equation are 45x + 62y = 3520 and 55x + 79y = 4415.

And we can form a matrix as

.

Step-by-step explanation:

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