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Step2247 [10]
3 years ago
10

How much is one melon if 3 sell for $1.98 ?

Mathematics
2 answers:
Sonbull [250]3 years ago
8 0

Answer: $0.66


Step-by-step explanation: Just divide 3 / $1.98 and you will get $0.66.

Fairly simple, But the only thing I don't understand is why a melon is on sale for $0.66. Thats CHEAP! Give me 100 :)


Paha777 [63]3 years ago
3 0

Answer:

One melon is sold for $0.66

Step-by-step explanation:

3 melons were sold for = $1.98

We have to calculate the price of 1 melon.

To find the price of one melon we just divide 1.98 by 3.

1 melon was sold for = 1.98 ÷ 3 = $0.66

One melon is sold for $0.66

You can check your answer if 1 melon costs $0.66,

3 melon costs 0.66 × 3 = $1.98

So the answer is correct.

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A line passes through the point (-6,9) and has a slope of 3/2. Write an equation in slope-intercept form for this line.
BaLLatris [955]

Answer:

y=3/2x+18

Step-by-step explanation:

Hi there!

We are given a point (-6,9) and a slope of 3/2

We want to write the equation of this line in slope-intercept form

Slope-intercept form is written as y=mx+b, where m is the slope and b is the y intercept

Since we already know the slope of the line as 3/2, we can substitute it as m into the equation:

y=3/2x+b

Now let's find  b

Since the equation of the line passes through (-6,9), we can use it to help solve for b

Substitute -6 as x and 9 as y:

9=3/2(-6)+b

Multiply

9=-9+b

Add 9 to both sides

18=b

Substitute 18 as b into the equation.

y=3/2x+18

Hope this helps!

7 0
2 years ago
Please help show that the following are TRUE.
mafiozo [28]

Answer:

  see below

Step-by-step explanation:

The formula for the sum of an infinite geometric series with first term a1 and common ratio r (where |r| < 1) is ...

  sum = a1/(1 -r)

Applying this to the given series, we get ...

a. sum = 5/(1 -3/4) = 5/(1/4) = 20

b. sum = d/(1 -1/t) = d/((t-1)/t) = dt/(t-1)

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The derivation of the above formula is in most texts on sequences and series. In general, you write an expression for the difference of the sum (S) and the product r·S. You find all terms of the series cancel except the first and last, and the last goes to zero in the limit, because r^∞ → 0 for |r| < 1. Hence you get ...

  S -rS = a1

  S = a1/(1 -r)

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3 years ago
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