All categories

3 years ago

How much is one melon if 3 sell for $1.98 ?

Mathematics

2 answers:

Sonbull [250]3 years ago

8 0

Answer: $0.66

Step-by-step explanation: Just divide 3 / $1.98 and you will get $0.66.

Fairly simple, But the only thing I don't understand is why a melon is on sale for $0.66. Thats CHEAP! Give me 100 :)

Paha777 [63]3 years ago

3 0

Answer:

One melon is sold for $0.66

Step-by-step explanation:

3 melons were sold for = $1.98

We have to calculate the price of 1 melon.

To find the price of one melon we just divide 1.98 by 3.

1 melon was sold for = 1.98 ÷ 3 = $0.66

One melon is sold for $0.66

You can check your answer if 1 melon costs $0.66,

3 melon costs 0.66 × 3 = $1.98

So the answer is correct.

You might be interested in

Matt built a cage for his snake. The top of the cage was in the shape of a right triangle. One leg of the top was 4x + 2 feet. T

mihalych1998 [28]

We can do S=1/2 of (4x+2)+4 * (3x+1) +4. All we are doing is adding 4 feet. I believe you are able to simplify it to 1/2 of 4x+6 * 3x+5

6 0

3 years ago

Which of the following is not a solution of 10 > x – 7y?

ASHA 777 [7]

D.
10>(12)-7(0)

10>12.... False

7 0

3 years ago

How many meters in 25cm x8

sukhopar [10]

$25cm*8\to \boxed{200cm} \\\\ 1m......100cm\\ x.........200cm \\\\ x=\frac{200cm*1m}{100cm} \\\\ x=1*2m \\\\ \boxed{\boxed{x=2m}}$

6 0

3 years ago

Read 2 more answers

it took Bob 55 minutes to clean the garbage. How many seconds did it take bob?there are 60 seconds in one minute please help me

defon

Answer:

3,300 sec

Step-by-step explanation:

7 0

3 years ago

Please Help !!Mr. Mudd gives each of his children $2000 to invest as part of a friendly family competition. The competition will

VikaD [51]

Answer:

Albert = $2159.07; Marie = $2244.99; Hans = $2188.35; Max = $2147.40

Marie is $10 000 richer

Step-by-step explanation:

Albert

(a) $1000 at 1.2 % compounded monthly

$A = P\left(1 + \dfrac{r}{n}\right)^{nt}$

A = 1000(1 + 0.001)¹²⁰ = $1127.43

(b) $500 losing 2%

0.98 × 500 = $490

(c) $500 compounded continuously at 0.8%

$\begin{array}{rcl}A & = & Pe^{rt}\\& = & 500e^{0.008 \times 10}\\& = &\mathbf{\$541.64}\\\end{array}\\$

(d) Balance

Total = 1127.43 + 490.00+ 541.64 = $2159.07

Marie

(a) 1500 at 1.4 % compounded quarterly

A = 1500(1 + 0.0035)⁴⁰ = $1724.99

(b) $500 gaining 4 %

1.04 × 500 = $520.00

(c) Balance

Total = 1724.99 + 520.00 = $2244.99

Hans

$2000 compounded continuously at 0.9 %

$\begin{array}{rcl}A& = &2000e^{0.009 \times 10}\\& = &\mathbf{\$2188.35}\\\end{array}\\$

Max

(a) $1000 decreasing exponentially at 0.5 % annually

A = 1000(1 - 0.005)¹⁰= $951.11

(b) $1000 at 1.8 % compounded biannually

A = 1000(1 + 0.009)²⁰ = $1196.29

(c) Balance

Total = 951.11 + 1196.29 = $2147.40

Marie is $ 10 000 richer at the end of the competition.

7 0

3 years ago