Hey!
So the number between needs to be the same number away from 23 and 49. 18 is less than 23 and 49 but we need a number between 23 and 49, so thats a no. same with 72.
Now we are left with 36 and 29.5.
well 29.5 is 6.5 points away from 23 but it is 19.5 points away from 49. So thats a no too because the difference is not the same.
now 36 is 13 away from 23 and also 13 away from 49 and the difference is the same
So the answer is C!
Hope this helps!
Answer:
Multiply everything by 15 because when you divide 40 from 600 you get 15. We will only use the 2 numbers on the right of both samples. Then find the total of each row
<u>18 turns into 270| 10 truns into 150 </u>=420
<u>19 turns into 285| 7 turns into 105</u>=390
Headline A: Both samples show that over 300 students want to go after 8 am which makes the headline true.
Headline B: 8:30 is actually the most popular start time because both samples show greater amount of students choose 8:30 as the start time than any other time.
Headline C: This statement is not supported by the data, the data shows that 7:45 am is the second most popular selection.
Headline D: This statement is not supported by the data because both samples show that over 100 people chose 9:00.
I hope this is a good answer for you and I hope you have a nice day.
P.S. Please mark me braineast!
Answer:
a<-4
Step-by-step explanation:
To solve this, you have to isolate a. This means you will have to add 5 to both sides. This will make the equation -2a>8. Divide both sides by 2 to get -a>4. Divide each side by -1 to get a>-4. Because you have to flip the sign when you divide by a negative number, you have to change it into a<-4.
If this has helped please mark as brainliest
Answer:
D
Step-by-step explanation:
The range is all of the y values that make a function true. Our graph here starts at y=-2 and then goes up for infinity. This means the range is y ≥ -2. The domain is [0, ∞) because our x values start at 0 and go to infinity. This means the domain is restricted so A is not true, B is not true because the graph does not exist at x = -2.
