As e is point between df. So we can write df as
df = de + ef
As given df = 78 , de = 5x - 9 , ef = 2x + 10.
So we can write
78 = 5x - 9 + 2x + 10
78 = 7x + 1
On subtracting 1 on booth side
78 - 1 = 7x +1 - 1
77 = 7x
On dividing both side by 7.

11 = x
So x = 11.
So ef = 2x + 10 = 2*11 + 10 = 22 + 10 = 32
Answer:
8πcm² = 8pi cm²
Step-by-step explanation:
The formula for area of a sector = ½r²θ
Where r = radius = 6cm
θ = central angle = 4pi/9 in radians = 4π/9
Area of the sector = 1/2 × 6² × 4π/9
Area of the sector = (144π/18)cm²
Area of the sector = 8πcm²
Therefore, Area of the sector =
8πcm² = 8pi cm²
ANSWER : 41/25 or in simplest form 1 16/25 . it could also be 1.64 in decimal form .
10 because 8 squares plus 6 squared equals 100 and the root of 100 is ten
Answer: -10 I think
Step-by-step explanation: