{3x + 4y = 36 {y = -1/2x + 8

6

bezimeni [28]

Answer:

260 stickers

Step-by-step explanation:

Let Gareth's stickers be x.

Hence Cheryl sticker is 160+x;

If Cheryl gave 185 stickers

to Gareth, it means:

Cheryl has at the moment;

160 + x - 185 = x - 25

At this time when Gareth receives 185 he now has:

x+ 185

Also when he receives x +185, he has 3 times Cherry's meaning:

x+185 =3(x-25)

x + 185 = 3x -75

185 + 75 = 3x-2x

260= x

x = 260.

Hence Gareth has 260 stickers

5 0

2 years ago

The length of one side of a square pond is 15 feet. The pond is surrounded by a 3 foot wide walkway. What is the total area of t

rewona [7]

Answer:

Area = 324 ft²

Step-by-step explanation:

Given

Length = 15ft

Walkway = 3ft

Required

Determine the area of the pond + the walkway

To calculate the required area, we need to get the total length of a side .

This is calculated by adding the length of a side of the pond and the side of the walkway

Total Length = Pond Length + Walkway

Total Length = 15ft + 3ft

Total Length = 18ft

Now, the required area can be calculated as thus:

Area = Total Length * Total Length

Area = 18ft * 18ft

Area = 324 ft²

8 0

2 years ago

QUICK PLZZ!!! If m<ABD = 71°, what are m<ABC and m<DBC?

suter [353]

Answer:

m<ABC = 45

m<DBC = 34°

Step-by-step explanation:

Given:

m<ABD = 79°

m<ABC = (8x - 3)°

m<DBC = (5x + 4)°

Step 1: Generate an equation to find the value of x

m<ABC + m<DBC = m<ABD (angle addition postulate)

(8x - 3) + (5x + 4) = 79

Solve for x

8x - 3 + 5x + 4 = 79

13x + 1 = 79

Subtract 1 from both sides

13x + 1 - 1 = 79 - 1

13x = 78

Divide both sides by 13

x = 6

Step 2: find m<ABC and m<DBC by plugging the value of x into the expression of each angle

m<ABC = (8x - 3)°

m<ABC = 8(6) - 3 = 48 - 3 = 45°

m<DBC = (5x + 4)°

m<DBC = 5(6) + 4 = 30 + 4 = 34°

Step-by-step explanation:

!!

7 0

2 years ago

Two different suppliers, A and B, provide a manufacturer with the same part. All supplies of this part are kept in a large bin.

koban [17]

Answer:

The probability of selecting a non-defective part provided by supplier A is 0.807.

Step-by-step explanation:

Let A = a part is supplied by supplier A, B = a part is supplied by supplier B and D = a part is defective.

Given:

P (D|A) = 0.05, P(D|B) = 0.09

A supplies four times as many parts as B, i.e. n (A) = 4 and n (B) = 1.

Then the probability of event A and B is:

$P(A)=\frac{n(A)}{n(A)+N(B)}= \frac{4}{4+1}=0.80\\P(B)\frac{n(B)}{n(A)+N(B)}= \frac{1}{4+1}=0.20$

Compute the probability of selecting a defective product:

$P(D)=P(D|A)P(A)+P(D|B)P(B)\\=(0.05\times0.80)+(0.09\times0.20)\\=0.058$

The probability of selecting a non-defective part provided by supplier A is:

$P(A|D')=\frac{P(D'|A)P(A)}{P(D')} = \frac{(1-P(D|A))P(A)}{1-P(D)}\\=\frac{(1-0.05)\times0.80}{(1-0.058)}\\ =0.80679\\\approx0.807$

Thus, the probability of selecting a non-defective part provided by supplier A is 0.807.

5 0

3 years ago

Distribute the expression (u - 6) x 4.

valkas [14]

4u-24 because you have to take 4 and multiply it by your things inside your parentheses

4 0

3 years ago

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