Which point lies on the y-axis?

Solve (x – 3)2 = 49. Select the values of x. –46 -4 10 52

Fudgin [204]

Answer: x = 55/2

Step-by-step explanation: (x)(2) (-3)(2) = 49 2x-6+6 = 49+6 2x/2 = 55/2 x = 55/2

I know that my answer isn't a choice for one of the values of x but that's the result that I got when I solved (x–3)2 = 49.

6 0

2 years ago

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

marusya05 [52]

Answer:

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

$0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131$

$0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169$

And the 90% confidence interval would be given (0.131;0.169).

Step-by-step explanation:

We have the following info given:

$n= 955$ represent the sampel size slected

$x = 812$ number of students who read above the eighth grade level

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

The confidence interval for the proportion would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the significance is $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution and we got.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131$

$0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169$

And the 90% confidence interval would be given (0.131;0.169).

8 0

3 years ago

Plz help will be thanked and will pick out brainly

Brums [2.3K]

The answer is 32
Hope this helps:D
have a great rest of a brainly day!

5 0

2 years ago

Given the function defined in the table below, find the average rate of change, in the simplest form, of the function over the i

vekshin1

Answer:

im stuck on that question too funny bc im in your class and caught u cheating

Step-by-step explanation:

4 0

2 years ago

A farmer builds a fence to enclose a rectangular pasture.He uses 155 feet of fence. Find the total area of the pasture if it is

ICE Princess25 [194]

The area for the perimeter of a rectangle is:
<em>P = 2l + 2w</em>
In this problem, we are given that P = 155 and l = 45.5. To solve for area, we must find w. To do this, plug in the given info and isolate the w like so:
$155=2(45.5)+2w \\ 155=91+2w \\ (155)-91=(91+2w)-91 \\ 64=2w \\ \frac{64}{2} = \frac{2w}{2} \\ w=32$
Now we know w = 32. Knowing all the necessary info, we can use the area formula, <em>A=lw</em>, to solve for A.
$A=(45.5)(35) \\ A=1,456$

The area is 1,456 sq ft.

Hope this helps!

5 0

3 years ago