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bixtya [17]
3 years ago
12

Plz help and show work

Mathematics
1 answer:
Leya [2.2K]3 years ago
8 0

1. 1/6x +2/.8

2. .5u+3u

3. 4.5q/9

4. 0.6(.5x)

5. 5x x1.2

6. 7zx1/3

7. 0.24w + 0.5y

8. 0.75v-6(2/9y)

9. 0.25(2p+11)


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Since ABCD is a parallelogram, the two pairs of _________ sides (AB¯ and CD¯, as well as AD¯ and BC¯) are congruent. Then, since
Marysya12 [62]

Answer:

1. Opposite

2. angle-side-angle criterion

Step-by-step explanation:

Since ABCD is a parallelogram, the two pairs of <u>(opposite)</u> sides (AB¯ and CD¯, as well as AD¯ and BC¯) are congruent. Then, since ∠9 and ∠11 are vertical angles, it can be concluded that ∠9≅∠11. Since ABCD is a parallelogram, AB¯∥CD¯. Since ∠2 and ∠5 are alternate interior angles along these parallel lines, the Alternate Interior Angles Theorem allows that ∠2≅∠5. Since two angles of △AEB are congruent to two angles of △CED, the Third Angles Theorem supports that ∠8≅∠3. Therefore, using the <u>(angle-side-angle criterion)</u>, it can be stated that △AEB≅△CED. Then, applying the definition of congruent triangles, it can be stated that AE¯≅CE¯, which makes E the midpoint of AC¯. Use a similar argument to prove that △AED≅△CEB; then it can be concluded that E is also the midpoint of BD¯. Since the midpoint of both line segments is the same point, the segments bisect each other by definition. Match each number (1 and 2) with the word or phrase that correctly fills in the corresponding blank in the proof.

A parallelogram posses the following features:

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) Evaluating a polynomial limit analytically You should have learned by now the process for finding the derivative of a polynomi
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Answer:

This code or is program to find a given value of derivative of  a polynomial.

Step-by-step explanation:

We know already how to apply or make the procedures mathematically talking so this short program will eventually help you how to find logic.

// libraries

#include <stdio.h>

#include <conio.h>

//use to control floating elements

float poly(float a[], int, float);

//main

int main()

{

// Enter the degree of polynomial equation

float x, a[10], y1;

int deg, i;

printf("Enter the degree of polynomial equation: ");

scanf("%d", &deg);

printf("Ehter the value of x for which the equation is to be evaluated: ");

// Enter the coefficient of x to the power

scanf("%f", &x);

for(i=0; i<=deg; i++)

{

 printf("Enter the coefficient of x to the power %d: ",i);

 scanf("%f",&a[i]);

}

// The value of polynomial equation for the value of x

y1 = poly(a, deg, x);

 

printf("The value of polynomial equation for the value of x = %.2f is: %.2f",x,y1);

 

return 0;

}

/* function for finding the value of polynomial at some value of x */

float poly(float a[], int deg, float x)

{

float p;

int i;

 

p = a[deg];

 

for(i=deg;i>=1;i--)

{

 p = (a[i-1] + x*p);

}

 

return p;

}

8 0
3 years ago
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Flura [38]
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3 years ago
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