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3 years ago

Pls help a girl outttt

Mathematics

2 answers:

Effectus [21]3 years ago

6 0

I believe the last answer would be correct.

Genrish500 [490]3 years ago

5 0

Answer:

95 Degrees Celsius

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A private ship carries two types of cargo: large crates and extra-large crates. Each type of crate weighs a specific amount.

Arisa [49]

Answer:

G. 32

Step-by-step explanation:

32 x 335 = 10720

16,100 - 10720 = 5380/190 = 28.3157894737

275 x 32 = 8800

18,800 - 8800 = 10,000/400 = 25 (This is the closer).

30 x 335 = 10,050

16,100 - 10,050 = 6050/190 = 31.8421052632

30 x 275 = 8250

18,800 - 8250 = 10550/400 = 26.375 (Same reason why it does't work)

25 x 335 = 8375

16,100 - 8375 = 7725/190 = 40.6578947368

25 x 275 = 6875

18,800 - 6875 = 11925/400 = 29.8125

24 x 335 = 8040

16,100 - 8040 = 8060/190 = 42.4210526316

24 x 275 = 6600

18,800 - 6600 = 12200/400 = 30.5

8 0

3 years ago

Solve the following equation for x. 12x - 8 = 40 A. 4 B. 5 C. 6 D. 3

Anon25 [30]

Add 8 to both sides

12x = 40 + 8

Simplify 40 + 8 to 48

12x = 48

Divide both sides by 12

x = 48/12

Simplify 48/12 to 4

x = 4

Answer: A. 4

7 0

3 years ago

Read 2 more answers

Solving quadratic equations using square roots (2/5)(x+3)^2=5

Slav-nsk [51]

$x = - 3 + \frac{5 \sqrt{2} }{2} \\ - 3 - \frac{5 \sqrt{2} }{2}$
$x = .5355339 \\ - 6.5355339$

I think that's what your looking for

6 0

3 years ago

Find the unknown angle measure by solving for the given variable

tiny-mole [99]

A straight line is 180°. So you can do:

(15x - 4) + (5x - 8) = 180 Simplify

20x - 12 = 180

20x = 192 Find the value of x

x = 9.6

m∠ABD = 15x - 4 Plug in x = 9.6

m∠ABD = 15(9.6) - 4 = 144 - 4 = 140°

m∠DBC = 5x - 8 Plug in 9.6

m∠DBC = 5(9.6) - 8 = 48 - 8 = 40°

3 0

3 years ago

If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.

Lelechka [254]

Answer:

$\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }$

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

$f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)$

So we can say that

$a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}$

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

$(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab$

and we can notice that

$a^2+b^2=(a+b)^2-2ab$ so

$(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab$

it comes

$x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}$

multiply by 3

$3x^2-20x+2*16+5=3x^2-20x+37$

4 0

3 years ago