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inna [77]
3 years ago
11

When writing a linear equation in standard form, what other forms might you need to use?

Mathematics
2 answers:
wlad13 [49]3 years ago
5 0

Answer:

there are 2 other forms, point-slope form and slope-intercept form.

Step-by-step explanation:

standard is Ax + By =C

point-slope is y-y_{1} =m(x-x_{1})

slope-intercept is y=mx+b

leva [86]3 years ago
3 0
<h3>Answer</h3><h3 /><h3>There are three major forms of linear equations: point-slope form, standard form, and slope-intercept form. We review all three in this article. There are three main forms of linear equations.</h3><h3 /><h3 /><h3 />
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Use the domain and range of each of the following relations to determine which is a function.
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B and C (I think they are the same)
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What is the fifth term in the geometric sequence described by this explicit formula y=40×(-2)^(n-1)​
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Answer:

The fifth term is 620

Step-by-step explanation:

y=40×(-2)^(n-1)​

The 5th terms means n=5

y = 40 * (-2) ^ (5-1)

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3 years ago
What is a word phrase for -12t + 2
dmitriy555 [2]
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hope this helps
6 0
3 years ago
Read 2 more answers
In a collection of nickels, dimes, and quarters worth $6.90, the ratio of the number of nickels to dimes is 3:8. The ratio of th
dimulka [17.4K]
N=number of nickels
d=number of dimes
q=number of quarters

example
if n:d=3:8
lets say n=3 and d=8
3*8=8*3
so
8n=3d
slightly confusing but go with it, it migh make sense or it might not


n:d=3:8
8n=3d

d:q=4:5
5d=4q

solve for one of them
solve for nickels in first and quarters in second

8n=3d, n=(3/8)d
5d=4q, (4/5)d=q

5n+10d+25q=690
divide by 5 to make it easeir
n+2d+4q=138
sub (3/8)d for n
sub (4/5)d for q
(3/8)d+2d+5(5/4)d=138
(3/8)d+2d+25/4d=138

3/8+2+25/4=
3/8+16/2+50/8=
69/8

(69/8)d=138
times both sides by 8
69d=1104
divide both sides by 69
d=16

16 dimes
sub back

(5/4)d=q
(5/4)16=q
80/4=q
20=q

(3/8)d=n
(3/8)16=n
48/8=n
6=n



6 nickles
16 dimes
20 quarters
yah
8 0
3 years ago
This is the last one!
grigory [225]

Answer:

The answer is c i believe

Step-by-step explanation:

7 0
3 years ago
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