Answer:
Step-by-step explanation:
Angle JKL is similar to angle PQR. This means that the ratio of the length of each side of ∆JKL to the length of the corresponding side of ∆ PQR is constant. Therefore,
JK/PQ = KL/QR = JL/PR
Therefore,
x/28 = 38/42
Cross multiplying, it becomes
x × 42 = 28 × 38
42x = 1064
Dividing the left hand side and the right hand side of the equation by 42, it becomes
42x/42 = 1064/42
x = 25.33 rounded up to the nearest 2 decimal places.
The given system of equations is :
y=2x+14 ...(1)
−4x−y=4 ... (2)
We can solve the above system of equation by method of substitution. Frm equation (1) we have y=2x+14. So, first step is to substitute 2x+14 for y in equation (2). Hence,
-4x - (2x + 14) = 4
-4x - 2x - 14 = 4
- 6x -14 = 4 By combining the like terms.
-6x - 14 + 14 = 4 + 14 Add 14 to each sides of the equation.
- 6x = 18
Divide each sides -6.
x = -3.
Next step is to plug in x=-3 in equation (1) to get the value of y. Therefore,
y = 2(-3) + 14
= -6 +14
= 8
So, y=8.
Answer:
1 5/6
Step-by-step explanation:
Answer:
24
Step-by-step explanation:
its positive
Notice that if
, then
. Recall the definition of the derivative of a function
at a point
:
So the value of this limit is exactly the value of the derivative of
at
.
You have