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otez555 [7]
4 years ago
7

Someone help me please :’) thank u so much, I suck at math.

Mathematics
1 answer:
Nina [5.8K]4 years ago
3 0

18+2 = 20

20x3=60

60-100= -40

3x(18-2)-100=-40

negative forty

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What is the median of 73,45,88,90,90,81,83
viktelen [127]

Answer:

The median is 83.

Step-by-step explanation:

7 0
3 years ago
1 / 3 divided by 2 is equal to? (show your answer in fraction form)
alexgriva [62]

Answer:

1/6

Step-by-step explanation:

1/3 * 1/2 = 1/6

5 0
4 years ago
7 - 14x = 2x - 5<br> This is hard
gizmo_the_mogwai [7]

Answer:

3/4 = x

Step-by-step explanation:

7 - 14x = 2x - 5

+14x    +14x

_____________

7 =16x -5

+5     +5

__________-

12 = 16x

÷16   ÷16

__________

12/16 = x

-or-

3/4 = x

Hope this helped :D

6 0
3 years ago
Read 2 more answers
Public opinion in the large city of Bedrock is that 60 percent of the residents are in favor of increasing taxes to fund alterna
uysha [10]

Answer: 0.8461

Step-by-step explanation:

Let p be the proportion of residents are against the increase of taxes to fund alternatives to drug addiction treatment.

As per given , we have p=0.40

A random sample is taken with size : n= 400

Expecting sample proportion : \hat{p}=\dfrac{150}{400}=0.375

Now , the probability that more than 150 of the residents surveyed will be against increasing taxes if a random sample of 400 residents are surveyed will be :

P(p>0.375)=P(\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}>\dfrac{0.375-0.40}{\sqrt{\dfrac{0.40(0.60)}{400}}})

=P(z>\dfrac{0.375-0.40}{\sqrt{\dfrac{0.40(0.60)}{400}}})\ \ [\because\ z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}]

=P(z>-1.02)=P(z-z)=P(Z

\approx0.8461  [By z-table]

Hence, the approximate probability that more than 150 of the residents surveyed will be against increasing taxes if a random sample of 400 residents are surveyed is 0.8461 .

4 0
4 years ago
12.what is the probability that a boy and a girl chosen randsomly will be seniors?
zhenek [66]

\frac{\textbf{1}}{\textbf{20}}

Step-by-step explanation:

Probability=\frac{\text{number of favourable outcomes}}{\text{total number of outcomes}}

Probability for a randomly chosen girl to be senior=\frac{\text{number of senior girls}}{\text{total number of girls}}

Probability for a randomly chosen girl to be senior=\frac{7}{8+11+9+7}=\frac{7}{35}=\frac{1}{5}

Probability for a randomly chosen boy to be senior=\frac{\text{number of senior boys}}{\text{total number of boys}}

Probability for a randomly chosen girl to be senior=\frac{9}{10+7+10+9}=\frac{9}{36}=\frac{1}{4}

For two independent events,

Probability for both event 1 and event 2 to take place=\text{probability of event 1} \times \text{probability of event 2}

Since choosing boys and girls is independent,

Probability for both boy an girl chosen to be senior=\text{probability for boy to be senior}\times\text{probability for girl to be senior}

Probability for both boy and girl chosen to be senior=\frac{1}{5} \times \frac{1}{4} = \frac{1}{20}

So,required probability is \frac{1}{20}

3 0
3 years ago
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